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Semmy [17]
3 years ago
7

Can somebody help me What is 4(x-1)=6

Mathematics
1 answer:
avanturin [10]3 years ago
7 0
4(x-1)=6 you start by dividing the whole equation by 4, so
x-1=6/4 simplify, x-1=3/2 then you add 1 to the whole equation
x=1 and 3/2 or x=5/2
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Someone solve and show your work. Thanks! I’m giving brainliest.
Dmitry [639]
Lol i was working on this earlier. First get rid of the parenthesis by distributing the powers to the other powers.

27/4x(6)y(8)
the () are for powers



3 0
2 years ago
Dr. David Smith lived 1/13 of his life as a child. He spent 4/39 of his life preparing for an outstanding
stich3 [128]

Answer:

40 14/25 years

Step-by-step explanation:

Well, this certainly is fun.

First, to find the fraction of the doctor's life which 13 years represents, subtract the fractions from 1 (and in this case l stands for lifetime):

13 = (1 - (\frac{1}{13} + \frac{4}{39} + \frac{1}{2}))(l)

13 = (\frac{25}{78})(l)

So, multiply this equation by the reciprocal of 25/78 to isolate one of l:

13(\frac{78}{25}) = l

l = 40\frac{14}{25} years

4 0
2 years ago
A sample of n = 4 scores is selected from a population with m = 40 with s = 8, and the sample mean is M = 43. What is the standa
vladimir2022 [97]
Standard error (SE)
se=   \frac{s}{ \sqrt{n} }
Or

se =  \sqrt{ \frac{ {s}^{2} }{n} }

Therefore, SE of the mean = (8)/(2) =4
5 0
2 years ago
The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of
Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

AV = \frac{y(t2) - y(t1)}{t2 - t1}

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii)  t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8

So the average speed is -128.9 ft/s

iii)  t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

3 0
3 years ago
Which of the following inequalities matches the graph? PLZ HELP DUE TODAY
balandron [24]

Answer:

A. 2x + y < 7

Step-by-step explanation:

the slope is negative and the y-intercept is positive

6 0
2 years ago
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