Find all angles, 0 ≤C<360 that satisfy the equation below, to the nearest tenth of a degree.

Mathematics

1 answer:

ludmilkaskok [199]4 years ago

7 0

Move all the terms involving the sine to one side, and all the numbers to the other:

$9\sin(c)-2=\sin(c)-7 \iff 8\sin(c) = -5\iff \sin(c)=-\dfrac{5}{8} \iff c = \arcsin\left(-\dfrac{5}{8}\right)\approx 321.3$

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Step-by-step explanation:

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Neko [114]

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Step-by-step explanation:

This right triangle is a 30-60-90 triangle. This is a special triangle. Since this is a special triangle, the hypotenuse is 2x.

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AleksandrR [38]

For this question we have to take LCM of the fractions to simplify it and process further. So, by LaTeX interpreter equation editor, Here we go.

$\mathbf{Least \: Common \: Multiplier: 3x}$

$\mathbf{\dfrac{2}{x} \times 3x + \dfrac{1}{3} \times 3x - \dfrac{4}{x} \times 3x}$

Combine the fractions to multiply the numerator.

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$\mathbf{\dfrac{6x}{x} + \dfrac{3}{3}x = \dfrac{12x}{x}}$

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Just subtract both of the current sides by the numbered value "6".

$\mathbf{6 + x - 6 = 12 - 6}$

$\boxed{\underline{\mathbf{Final \: \: Answer: \: x = 6}}}$

Hope it helps.

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