If the sample size of population is 24 then the number of degrees of freedom for reading the t value is 23 which is option c.
Given sample size of 24,mean 23.
We have to determine the number of degrees of freedom which will be used to find the critical values of t.
Degree of freedom is the number of values in the final calculation of a statistic that are free to vary means that can change their values in the formula of calculating t.
t=(X-μ)/s/
where X is sample mean ,
μ is hypothsised population mean
s is sample standard deviation
n is sample size.
Degree of freedom=n-1
In this question n is 24 so the degree of freedom =24-1=23.
Hence the number of degrees of freedom for reading the t value is 23.
Learn more about degree of freedom at brainly.com/question/17305237
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Answer:

Step-by-step explanation:
Given expression,

=>
We see that
is common in both numerator and denominator
hence canceling out we get:-

Answer=
Answer:
I'm not pretty sure but I think is the second option, B
Answer:
Rate of depreciation per year is 4310 $/ year and the depreciation schedule is given below.
Step-by-step explanation:
According to the question,
since, it is straight-line depreciation,
rate of depreciation per year =
$/year
= 4310 $/ year
So we can prepare the following table. (year = 0 for the base period)
Year Depreciation Accumulated Book value
expense depreciation
( in $) (in $) (in $)
0 0 0 21920
1 4310 4310 17610
2 4310 8620 13300
3 4310 12930 8990
4 4310 17240 4680