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galina1969 [7]
3 years ago
9

Mike's car broke down 5 miles from the auto shop. If he can push his car 1,056 feet per hour, how many hours will it take him to

reach the auto shop?
Mathematics
1 answer:
Alinara [238K]3 years ago
3 0

Answer:

It'll take 25 hours to get to the auto shop

Step-by-step explanation:

Given

Distance = 5 miles

Speed =1056 feet per hour

Required

How long will it take to the auto shop

This can be solved using Speed's formula;

Speed = \frac{Distance}{Time}

Substitute values for Speed and Distance

\frac{1056 ft}{hr} = \frac{5 miles}{Time}

1 mile = 5280 feet;

So:

\frac{1056 ft}{hr} = \frac{5 * 5280 ft}{Time}

\frac{1056 ft}{hr} = \frac{26400ft}{Time}

Cross Multiply

Time * 1056ft = 26400ft * hr

Divide both sides by 1056ft

Time * \frac{1056ft}{1056ft} = \frac{26400ft * hr}{1056ft}

Time = \frac{26400ft * hr}{1056ft}

Time = 25hr

<em>Hence, it'll take 25 hours to get to the auto shop</em>

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zhenek [66]

Answer:

2

Step-by-step explanation:

(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{x+2}

\frac{3^6}{4^6} \cdot \frac{16^5}{9^5}=\frac{4^{x+2}}{3^{x+2}}

\frac{3^6}{4^6} \cdot \frac{(4^2)^5}{(3^2)^5}=\frac{4^{x+2}}{3^{x+2}}

\frac{3^6}{4^6} \cdot \frac{4^{10}}{3^{10}}=\frac{4^{x+2}}{3^{x+2}}

\frac{3^6}{3^{10}} \cdot \frac{4^{10}}{4^6}=\frac{4^{x+2}}{3^{x+2}}

3^{-4} \cdot 4^{4}=4^{x+2}3^{-(x+2)}

This implies

x+2=4

and

-(x+2)=-4.

x+2=4 implies x=2 since subtract 2 on both sides gives us x=2.

Solving -(x+2)=-4 should give us the same value.

Multiply both sides by -1:

x+2=4

It is the same equation as the other.

You will get x=2 either way.

Let's check:

(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{2+2}

(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{4}

Put both sides into your calculator and see if you get the same thing on both sides:

Left hand side gives 256/81.

Right hand side gives 256/81.

Both side are indeed the same for x=2.

4 0
3 years ago
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Delvig [45]
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now just multiply 25 by 12 ( 12 lots of 10 minutes in 2 hours)
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