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3 years ago

11

Can someone answer fast.plsss

1 answer:

Anika [276]3 years ago

4 0

Answer:

a

Step-by-step explanation:

sec (thita) = squrt (5)

squaring on both sides:

sec^2 (thita) = 5 - equation 1

1 + tan^2 (thita) = 5

tan^2 (thita) = 4

tan (thita) = 2.

= tan (thita) - squrt(5)sin(thita)

= 2 - squrt(5) x 2/ squrt(5)

= 0

from eqn - 1

sec(thita) = squrt(5)

cos(thita) = 1/ squrt(5)

sin(thita) = squrt ( 1- 1/(squrt (5))^2)

sin(thita) = 2/ squrt(5) .

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Can someone help idk if this is right

navik [9.2K]

Answer:

$a_n=-3 \cdot a_{n-1}$

$a_1=2$

You gave the explicit form.

Step-by-step explanation:

You gave the explicit form.

The recursive form is giving you a term in terms of previous terms of the sequence.

So the recursive form of a geometric sequence is $a_n=r \cdot a_{n-1}$ and they also give a term of the sequence; like first term is such and such number. All this says is to get a term in the sequence you just multiply previous term by the common ratio.

r is the common ratio and can found by choosing a term and dividing by the term that is right before it.

So here r=-3 since all of these say that it does:

-54/18

18/-6

-6/2

If these quotients didn't match, then it wouldn't be geometric.

Anyways the recursive form for this geometric sequence is

$a_n=-3 \cdot a_{n-1}$

$a_1=2$

5 0

3 years ago

Monique's son just turned 2 years old and is 34 inches tall. Monique heard that the average boy will grow approximately 2 5/8 in

tatuchka [14]

Answer:

The equation representing how old Monique son is $\mathbf{a = 2 + \dfrac{8}{21}(q-34)}$

Step-by-step explanation:

From the given information:

A linear function can be used to represent the constant growth rate of Monique Son.

i.e.

$q(t) = \hat q \times t + q_o$

where;

$q_o$ = initial height of Monique's son

$\hat q$ = growth rate (in)

t = time

So, the average boy grows approximately 2 5/8 inches in a year.

i.e.

$\hat q = 2 \dfrac{5}{8} \ in/yr$

$\hat q = \dfrac{21}{8} \ in/yr$

Then; from the equation $q(t) = \hat q \times t + q_o$

$34 = \dfrac{21}{8} \times 0 + q_o$

$q_o = 34\ inches$

The height of the son as a function of the age can now be expressed as:

$q(t) = \dfrac{21}{8} \times t + 34$

Then:

Making t the subject;

$q - 34 = \dfrac{21}{8} \times t$

$t = \dfrac{8}{21}(q-34)$

and the age of the son i.e. ( a (in years)) is:

a = 2 + t

So;

$\mathbf{a = 2 + \dfrac{8}{21}(q-34)}$

SO;

if q (growth rate) = 50 inches tall

Then;

$\mathbf{a = 2 + \dfrac{8}{21}(50-34)}$

$\mathbf{a = 2 + \dfrac{8}{21}(16)}$

a = 2 + 6.095

a = 8.095 years

a ≅ 8 years

i.e.

Monique son will be 8 years at the time Monique is 50 inches tall.

8 0

2 years ago

Drupady [299]

Answer: $d(r) = 5(0.87)^r$

Step-by-step explanation:

7 0

3 years ago

Please i need help its for a grade

horsena [70]

The answer is 25 and make sure it’s correct

8 0

3 years ago

A cube has six sides that are numbered 1 to 6 the sides number 1 2 and 5 or green the sides number 3 4 and 6 red what is the pro

Arisa [49]

Answer:

5 / 6

Step-by-step explanation:

The green numbers: 1, 2, 5

The even numbers: 2, 4, 6

Since 2 is an overlap, we'll only count it once.

Total outcomes: 6

Successful outcomes: 5

Probability: 5 / 6

6 0

3 years ago