Answer:
3.125
Step-by-step explanation:
The correct answer to this open question is the following.
Unfortunately, you forgot to attach the scores shown in the back-to-back stem-and-leaf display. So we do not know what the numbers are and we do not have any reference at all
What we can do to help you is to comment on the following general terms.
There have been previous and similar experiments or projects like this in other schools in America. These results suggest that the new activities are better because extra or special reading comprehension programs better prepare students to understand what they are reading and comprehend more than basic ideas of the text.
Students that participate in these programs develop a better sense to understand and like what they are reading, considerably increasing their focus and attention.
These programs have resulted positively when trying to improve the marks of the students, compared to other traditional approaches.
Answer:
probably cuz its in parentheses but there's no picture
Step-by-step explanation:
Data that can only take particular values is called discrete data.
Data that can take on any value is called continuous data.
We use the Markov's inequality to solve for (a) and (b)
P(X > 18) = 16/18 = 8/9 or 0.8888 or 8.88%
P(X > 25) = 16/25 = 0.64 or 64%
For c, we use the z-score with the standard deviation as the square root of the variance
σ = √9 = 3
z = (X - μ) / σ
The limits are 10 and 22
For 10, the z-score is:
z = (10 - 16) / 3 = -2
For 22
z = (22 - 16) / 3 = 2
We use the z-score table to get the corresponding probability of the two limits and subtract the smaller probability from the bigger probability to get the actual probability. So, from the z-score table:
for z = -2, P = 0.0228
for z = 2, P = 0.9772
0.9772 - 0.0228 = 0.9544
The probability is 0.9544 or 95.44%
For (d), we do the same thing but we subtract the obtained probability from 1 since the condition is that the sales exceed 18
z = (18 - 16) / 3 = 0.67 which correspond to P = 0.7486
1 - 0.7486 = 0.2514
The probability is 0.2514 or 25.14%