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Pepsi [2]
3 years ago
9

Factor 200t + 8t 3 - 80t 2. 8t(t - 5)(t + 5) 8t(t - 5)2 -8t(t - 5)(t + 5)

Mathematics
1 answer:
amid [387]3 years ago
3 0
200t + 8t^3 - 80t^2

8t(25 + t^2 - 10t) ....rearrange
8t(t^2 - 10t + 25)
8t(t - 5)(t - 5) 
8t(t - 5)^2 <==
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Answer:

117,600 ways

Step-by-step explanation:

This problem can be solved using fundamental principle of counting , according to which , if there are m different things and n different things,

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____________________________________

In the problem,\

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hence first member can be chosen in 50 ways

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second member cannot be from state A1, then number of state left = 49

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for simplicity lets take state A2,

Third member cannot be from state A1 and A2, then number of state left = 48

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