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Assoli18 [71]
3 years ago
8

There are 40 students in a class and 30% of these students passed their history test.

Mathematics
1 answer:
julsineya [31]3 years ago
5 0

Answer:

12 10

Step-by-step explanation:

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Brian correctly use a method of completing the square to solve the equation X a 2nd plus 7X -11 equals zero Brian‘s first step w
ArbitrLikvidat [17]

Answer:

(\frac{7}{2})^{2}

Step-by-step explanation:

Brain correctly use a method of completing the square to solve the equation:

x^2+7x-11=0

His First Step is to: Take the Constant Term to the Right Hand Side

x^2+7x=11

The Next Step Would be to:

  • Divide the Coefficient of x by 2
  • Square It
  • Add it to both Sides

In this case, the Coefficient of x  = 7

  • Divided by 2 = \frac{7}{2}
  • Squaring It, we have: (\frac{7}{2})^{2}

It is this number (\frac{7}{2})^{2} that is added to both sides in the manner below:

x^2+7x+(\frac{7}{2})^{2}=11+(\frac{7}{2})^{2}

6 0
4 years ago
Write an equation through the line point (-2,5) with slope 4
dybincka [34]

Answer:

Step-by-step explanation:

6 0
3 years ago
A triangle with sides 11m , 13m and 18m is a right triangle.<br> ​<br> A<br> True<br> B<br> False
Julli [10]

\bold{\huge{\pink{\underline{ Solution}}}}

\bold{\underline{ Given :-}}

  • <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>

\bold{\underline{ To \: Find :-}}

  • <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>

\bold{\underline{ Let's \: Begin :-}}

\sf{\red{ In \:right \:angled\ : triangle, }}

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>

\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}

\sf{(AB)² + (BC)² = (AC)²}

\sf{ (11)² + (13)² = (18)² }

\sf{ 121 + 169 ≠  324 }

\sf{ 290 ≠ 324  }

<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>

The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse

\sf{\blue{ Hence,\: Your\: answer \:is \:false }}

5 0
2 years ago
Chef Daniel had 431 ounces of chocolate frosting in his refrigerator. It takes 8 ounces of frosting to frost one cupcake. How ma
Alex

Answer:

53 cupcakes

Step-by-step explanation:

Take the amount of frosting and divide by the amount needed per cupcake

431/8

53.875

We round down since we cannot frost part of a cupcake

53 cupcakes

7 0
3 years ago
Read 2 more answers
HELP IM FAILING MATH I NEED HELP :(
CaHeK987 [17]

Answer:idk

Step-by-step explanation:

idk

7 0
3 years ago
Read 2 more answers
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