Help plzzzz :( quick if you can?
2 answers:
Answer:
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Q. What do you mean by like terms and unlike terms?
⇢ Like terms are those which have the same base whereas unlike terms are those which have the different base [ For eg : In 6p , 3r , 4p & 4r , 6p and 4p are like terms as they have the same base i.e p & 3r and 4r are like terms as they have the same base i.e r ] . Like terms can be added or subtracted as per the signs given and unlike terms are kept as they are. Only coefficient of like terms can be added or subtracted.
- Lets solve :
- The positive integers are always added and possess the positive ( + ) sign. For example : ( +2 ) + ( + 3 ) = + 5
- The negative integers are always added but possess the negative ( - ) sign . For example : ( - 5 ) + ( - 2 ) = - 7
- The negative and positive integers are always subtracted but possess the sign of the bigger integer. For example : ( + 7 ) + ( - 3 ) = 4
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Problem 1
With limits, you are looking to see what happens when x gets closer to some value. For example, as x gets closer to x = 2 (from the left and right side), then y is getting closer and closer to y = 1/2. Therefore the limiting value is 1/2
Another example: as x gets closer to x = 4 from the right hand side, the y value gets closer to y = 4. This y value is different if you approach x = 0 from the left side (y would approach y = 1/2)
Use examples like this and you'll get the results you see in "figure 1"
For any function values, you'll look for actual points on the graph. A point does not exist if there is an open circle. There is an open circle at x = 2 for instance, so that's why f(2) = UND. On the other hand, f(0) is defined and it is equal to 4 as the point (0,4) is on the function curve.
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Problem 2
This is basically an extension of problem 1. The same idea applies. See "figure 2" (in the attached images) for the answers.
With limits, you are looking to see what happens when x gets closer to some value. For example, as x gets closer to x = 2 (from the left and right side), then y is getting closer and closer to y = 1/2. Therefore the limiting value is 1/2
Another example: as x gets closer to x = 4 from the right hand side, the y value gets closer to y = 4. This y value is different if you approach x = 0 from the left side (y would approach y = 1/2)
Use examples like this and you'll get the results you see in "figure 1"
For any function values, you'll look for actual points on the graph. A point does not exist if there is an open circle. There is an open circle at x = 2 for instance, so that's why f(2) = UND. On the other hand, f(0) is defined and it is equal to 4 as the point (0,4) is on the function curve.
=======================================================
Problem 2
This is basically an extension of problem 1. The same idea applies. See "figure 2" (in the attached images) for the answers.