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3 years ago

Can someone explain how to do problems like (-2+4) or (4+ -6)

Mathematics

2 answers:

sladkih [1.3K]3 years ago

8 0

Answer:

Step-by-step explaination

-2 + 4 is 2 4+ -6 is -2

KiRa [710]3 years ago

4 0

Answer:

All you have to do is just add the numbers inside the parenthesis. (4+-2) is the same as 4-2 which is equal to 2. (4+-6) is the same as 4-6 which is equal to -2.

Step-by-step explanation:

If this has helped please mark as brainliest

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How many 3 digit numbers can you make using these numbers: 4,2,9 (numbers can be reapeated)

bogdanovich [222]

Answer:

You can make 27 different 3 digit numbers

Step-by-step explanation:

Since we can use 3 different numbers this means that each of the 3 digits can be one of the 3 numbers (4,2,9). This means that there are 3 different values for the first digit, 3 different values for the second digit, and 3 different values for the third digit, which mean that we can make 3 x 3 x 3 different 3 digit numbers (we took the number of possible values for each digit and multiplied them together.

3 x 3 x 3 = 27

8 0

3 years ago

What is the range of y = -xsquared2 - 2x + 3?

Flura [38]

Answer:

( - infinity, 4) thats the range hope it helps.

8 0

3 years ago

Read 2 more answers

9 t-shirts and a hat costs £93 4 t-shirts and a hat costs £43 how much does the hat and t-shirt cost

alexandr402 [8]

Answer:

T-shirt costs £10

Hat costs £3

Step-by-step explanation:

£93-£43=£50

9-4=5

£50/5=10

1 t-shirt=£10

£10x9=£90

£93-£90=£3

T-shirt = £10

Hat= £3

4 0

3 years ago

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What is the first step in simplifying the expression below?

zlopas [31]

Answer:

subtracting 1 from 3 is the correct answer of this question

6 0

3 years ago

Four equivalent forms of a quadratic function are given. Which form displays the zeros of function h?

taurus [48]

Step-by-step explanation:

As we know that $f$ is a polynomial function, the values of $x$ for which $f(x)=0$ are said to be the zeros of $f$ .

Factoring the polynomial equation, if it is eligible to get factored, setting each factor equal to zero and solving can determine the zeros.

So, it is clear from above that option A i.e. $h\left(x\right)=-4\left(x\:-\:2\right)\left(x\:+\:2\right)$ and option C i.e. $h\left(x\right)\:=\:4\left(x^2\:-\:4\right)$ displays the zeros of function h, as they can be factored by setting each factor equal to zero.

Option A)

Lets solve them to get the zeros of these functions.

Considering the function

$h\left(x\right)=-4\left(x\:-\:2\right)\left(x\:+\:2\right)$

$\mathrm{The\:roots\:are\:the\:intercepts\:with\:the\:x-axis}\:\left(y=0\right)$

$-4\left(x-2\right)\left(x+2\right)=0$

Using the Zero Factor Principle:

$\mathrm{ \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$\mathrm{Solve\:}\:x-2=0:\quad x=2$

$\mathrm{Solve\:}\:x+2=0:\quad x=-2$

$\mathrm{The\:zeros\:to\:the\:quadratic\:equation\:are:}$

$x=2,\:x=-2$

Option B)

Considering the function

$h\left(x\right)\:=\:4\left(x^2\:-\:4\right)$

$\mathrm{The\:roots\:are\:the\:intercepts\:with\:the\:x-axis}\:\left(y=0\right)$

$4\left(x^2-4\right)=0$

$\mathrm{Divide\:both\:sides\:by\:}4$

$\frac{4\left(x^2-4\right)}{4}=\frac{0}{4}$

$x^2-4=0$

$x^2=4$

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=\sqrt{4},\:x=-\sqrt{4}$

$x=2,\:x=-2$

Although the zeros of the function $h\left(x\right)=-4x^2\:+\:16$ can also be obtained for the function by similar method. But, for this we would have to solve them before determining the zeros.