Here first we have to understand which place is 10 thousand.
6- hundred thousand
2- ten thousand
0- thousand
0- hundred
0- ten
0- one
so as we can see 2 is in ten thousands place.
Now rounding ten thousands place is done by looking up to thousands place.
If the digit at thousands place is 5 or greater than 5 then we change our ten thousands value to one digit higher else it remains same.
Here we have 0 at thousands place , which is less than 5 , so we keep the number as it is.
Answer: 620, 000
6 1/12 would be the answer
Rewriting our equation with parts separated
1/3+5+3/4
Solving the fraction parts
1/3+3/4=?
Find the LCD of 1/3 and 3/4 and rewrite to solve with the equivalent fractions.
LCD = 12
4/12+9/12=13/12
Simplifying the fraction part, 13/12,
13/12=11/12
Combining the whole and fraction parts
5+1+1/12=6 1/12
Find the GCF of 24 and 30
24 30
1×24 1×30
2×12 2×15
3×8 3×10
4×6 5×6
The common factors are 1, 2, 3, and 6
That means we can make 6 necklaces, each necklace with 4 jade beads and 5 teak beads.
Answer:
Part A:




Part B:


and 
Step-by-step explanation:
Part A:
The inicial concentration of the lemonade is 50%, and the volume is 4 quarts, and we will add x quarts of a lemonade with a concentration of 100%, so the total volume will be y, and the concentration will be 0.7, so we have that:


Using the value of y from the first equation in the second one, we have:





Part B:
If he shoots a total of ten targets, we can write the equation:

Each stationary target is 2 points, and each moving target is 3 points, so if the total points is 23, we have:

If we subtract the second equation by two times the first one, we have:



⇒ 