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4 years ago

Select all pairs of corresponding angles. Assume the lines are parallel.

Mathematics

2 answers:

marta [7]4 years ago

8 0

Answer:

1 and 5 ,

2 and 6 ,

3 and 7 , and

4 and 8.

Elena-2011 [213]4 years ago

3 0

Step-by-step explanation:

Following are the pair of corresponding angles.

1 and 5

2 and 6

3 and 7

4 and 8

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Evaluate the expression for this

Zinaida [17]

Answer is

184
- ——-
25

7 0

2 years ago

-2(5p – 3) = 26 Explain your answer. 30 points.

otez555 [7]

The answer would be p= -2

To check it:
-2(5(-2) - 3) = 26
-2(-10-3) = 26
-2(-13) = 26
26 = 26

4 0

3 years ago

Find the midpoint of the segment that has endpoints at (a+b, a-b) and (a, b).

Hunter-Best [27]

Answer:

((2a+b)/2 , a/2)

Step-by-step explanation:

The midpoint is the mean/average of both the x and y values.

Our x values are a+b and a

Our y values are a-b and b

The midpoint x value is (a+b + a ) /2 = (2a + b)/2

The midpoint y value is (a-b + b) /2 = (a)/2

The midpoint combines these two values to get ((2a+b)/2 , a/2) as our midpoint

5 0

3 years ago

The equation y = \large 1\frac{1}{2}x represents the number of cups of dried fruit, y, needed to make x pounds of granola. Deter

Natasha2012 [34]

Answer:

$(1\frac{1}{2},1)$ - False

$(4,6)$ - True

$(18,12)$ -- False

$(0,0)$ -- True

$(2\frac{1}{2},3\frac{3}{4})$ -- True

Step-by-step explanation:

The points are

$(1\frac{1}{2},1)$ , $(4,6)$ , $(18,12)$ , $(0,0)$ and $(2\frac{1}{2},3\frac{3}{4})$ ---- missing from the question

Given

$y = 1\frac{1}{2}x$

Required

Determine if each of the points would be on $y = 1\frac{1}{2}x$

To do this, we simply substitute the value of x and of each point in $y = 1\frac{1}{2}x$ .

(a) $(1\frac{1}{2},1)$

In this case;

$x = 1\frac{1}{2}$ and $y = 1$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 1\frac{1}{2}$

$y = \frac{3}{2} * \frac{3}{2}$

$y = \frac{9}{4}$

$y = 2\frac{1}{4}$

The point $(1\frac{1}{2},1)$ won't be on the graph because the corresponding value of y for $x = 1\frac{1}{2}$ is $y = 2\frac{1}{4}$

(b) $(4,6)$

In this case;

$x = 4$

$y = 6$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 4$

$y = \frac{3}{2} * 4$

$y = \frac{3* 4}{2}$

$y = \frac{12}{2}$

$y = 6$

The point $(4,6)$ would be on the graph because the corresponding value of y for $x = 4$ is $y = 6$

(c) $(18,12)$

In this case:

$x = 18;y = 12$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 18$

$y = \frac{3}{2} * 18$

$y = \frac{3* 18}{2}$

$y = \frac{54}{2}$

$y = 27$

The point $(18,12)$ wouldn't be on the graph because the corresponding value of y for $x = 18$ is $y = 12$

(d) $(0,0)$

In this case;

$x =0; y = 0$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 0$

$y = 0$

The point $(0,0)$ would be on the graph because the corresponding value of y for $x = 0$ is $y = 0$

(e) $(2\frac{1}{2},3\frac{3}{4})$

In this case:

$x = 2\frac{1}{2}$ ; $y = 3\frac{3}{4}$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 2\frac{1}{2}$

$y = \frac{3}{2} * \frac{5}{2}$

$y = \frac{15}{4}$

$y = 3\frac{3}{4}$

The point $(2\frac{1}{2},3\frac{3}{4})$ would be on the graph because the corresponding value of y for $x = 2\frac{1}{2}$ is $y = 3\frac{3}{4}$

3 0

3 years ago

A kite descends to the ground from a height of 32 feet. Use an integer to describe the descent.

nydimaria [60]

32-x=0; with x equaling the amount descended or -32.

8 0

3 years ago