There are two c's. You must pay attention to capitalization, there's a lowercase c and an uppercase C which represent two different variables. Also, the W is capitalized which could make your answer incorrect if you don't use the same notation.

Solving for small c..

$C = \frac{Wtc}{1,000} \\\\ 1,000C = Wtc \\\\\frac{1,000C}{Wt}= c$

So it's the answer shown in the picture, but it should be a capital W instead of a lowercase w.

3 0

3 years ago

Prove: cot(x) sec^4(x) = cot(x) +2tan(x) + tan^3(x)

masha68 [24]

$\bf cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\qquad\qquad 
sec(\theta)=\cfrac{1}{cos(\theta)}\quad\qquad 1+tan^2(\theta)=sec^2(\theta)\\\\\\
tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}
\qquad \qquad cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\\\\
-------------------------------\\\\
cot(x)sec^4(x)=cot(x)+2tan(x)+tan^3(x)\\\\
-------------------------------\\\\$

$\bf \textit{so, let's do the left-hand-side}\\\\
cot(x)sec^2(x)sec^2(x)\implies cot(x)[1+tan^2(x)][1+tan^2(x)]
\\\\\\
cot(x)[1^2+2tan^2(x)+tan^4(x)]
\\\\\\
cot(x)+2tan^2(x)cot(x)+tan^4(x)cot(x)
\\\\\\
cot(x)+2\cdot \cfrac{sin^2(x)}{cos^2(x)}\cdot \cfrac{cos(x)}{sin(x)}+\cfrac{sin^4(x)}{cos^4(x)}\cdot \cfrac{cos(x)}{sin(x)}
\\\\\\
cot(x)+2\cdot \cfrac{sin(x)}{cos(x)}+\cfrac{sin^3(x)}{cos^3(x)}\implies \boxed{cot(x)+2tan(x)+tan^3(x)}$

8 0

3 years ago

-9 + k/10 = -10<br>I need to answer

Firdavs [7]

Answer:

k = -10

Step-by-step explanation:

-9 + k/10 = -10

-10/10 = -1

-9 + -1 = -10

k = -10

3 0

3 years ago

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FREE BRAINLIEST!! ill also answer questions that you have posted if you answer these 2 questions correctly!! ((Answer both quest

Gala2k [10]

Answer:

D and C

Step-by-step explanation:

I don't really know if my answers are even correct but I did some research on them. I don't want to waste your time --or mine.

3 0

3 years ago

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