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diamong [38]
3 years ago
7

Simplify (8 + 2i)(-5 + 6i)

Mathematics
2 answers:
zlopas [31]3 years ago
8 0

Answer:

12i^2+38i-40

Step-by-step explanation:

In this problem, you have to FOIL.

Which means that first you multiply the first term "8" in (8+2i) by the terms in (-5+6i)

so...

8 * -5

8*6i

And you get:

-40 + 48i

Then You multiply the second term "2i" by the terms in (-5+6i)

so...

2i*-5

2i*6i

And you get:

-10 +12i^2

Then you add like terms to get: 12i^2 +38i-40

Andru [333]3 years ago
7 0
Assuming ‘I’ is an imaginary unit . . .

Answer : -52 + 38i
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Please help
Firdavs [7]

Answer:

y = -x -3

Step-by-step explanation:

I went to Desmos and kept guessing y intercepts until the line passed through the point (-4, 1). Sorry I can't explain the real way to figure this out.

5 0
2 years ago
If log, 7 -3 what is the value of x?<br> A. 21<br> B. 3V7<br> C. 37<br> D. 343
gregori [183]

Answer:

B

Step-by-step explanation:

logₓ 7 = 3

x³ = 7

Take cube root both sides

x= \sqrt[3]{7}

4 0
2 years ago
I need help i have 5 minutes left of class i will give brainest if answer make sure to show poof ( If u lie i Will report you) =
kobusy [5.1K]

Answer:

circle question: 69.66

the other question: 66.8

Step-by-step explanation:

For the circle question:

the circle is inscribed in the square, so the diameter of the circle = side of the square

so we need to find the area of square and circle

then do this

square area - circle area

square area(side×side) = 324

circle area(pi×r^2)≈254.469

so shaded region = 69.66

__________

the other question:

we need to find the area of triangle and the area of the rectangle and add them together

A of Triangle (1/2×base×hight) = 34.32

A of rectangle (width × length) = 31.92

add them, so the answer will be = 66.8

4 0
3 years ago
An Electronics company packages is product in cube shaped boxes. These boxes are placed in to a larger box that measures 3 ft lo
Sergio [31]
= (3 * 1.25 * 2)/(0.25) ^ 3

= 7.5/(1/64)

= 480 boxes

Good luck :)
3 0
3 years ago
Find cos θ if sin θ = -12/13 and tan θ &gt; 0
Anarel [89]
SinФ=-12/13  
cosФ=Base/hypotenus
(hy)^2-(perpendicular)^2=(base)^2=13^2-12^2=5
cosФ=-5/13


6 0
3 years ago
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