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2 years ago

(07.03 LC)

Mathematics

1 answer:

ArbitrLikvidat [17]2 years ago

6 0

Answer:

2y - 16

Step-by-step explanation:

Trust me because i just got done doing my test and i got the question correctly.

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Divide £50 into the ratio 1:4

Helga [31]

Don't know how to type the symbole infront of the 50 so I will subsitute
£50=$50

so 1:4
add it up
1+4=5

so 5 total units
$50=5 units
divide by 5
$10=1 unit

so 1:4=10:10 times 4=10:40

the answer is 10:40

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2 years ago

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although she's only on middle school, Tamiya loves to drive Go-Karts her favorite place to go drive Go-Karts, Drivers Delight, h

levacccp [35]

Circumference = r * 2 * pi

Circumference of track 1 is 376.8

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2 years ago

I NEED HELP!! please show all work

PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

$4^{5x} = 3^{x-2}$

$\implies \log 4^{5x} = \log 3^{x-2}$

Drop the exponents:

$\implies 5x \log 4 = (x-2) \log 3$

Expand the right side:

$\implies 5x \log 4 = x \log 3 - 2 \log 3$

Move the terms containing x to the left side and factor out x :

$\implies 5x \log 4 - x \log 3 = - 2 \log 3$

$\implies x (5 \log 4 - \log 3) = - 2 \log 3$

Solve for x by dividing boths ides by 5 log(4) - log(3) :

$\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}$

You can stop there, or continue simplifying the solution by using properties of logarithms:

$\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }$

$\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }$

$\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}$

You can condense the solution further using the change-of-base identity,

$\implies \boxed{x = -\log_{\frac{1024}3}9}$

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2 years ago

The sum of 3 times a number and 5 is equal to 9.

tiny-mole [99]

Answer:

Let x equal “a number”

3x+5=9

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2 years ago

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I need help with Which table shows the correct methods used to justify the solution steps?

12345 [234]

Answer:

x = 8

Step-by-step explanation:

3 (x - 5) + 7x = 65

3x - 15 + 7x = 65

10x - 15 = 65

10x = 80

x = 8

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2 years ago

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