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SSSSS [86.1K]
3 years ago
12

Please help with the steps as well!!

Mathematics
1 answer:
mariarad [96]3 years ago
4 0

To solve this problem, we need to use the Pythagorean Theorem, which states that a^2 + b^2 must equal c^2. "a" is the length of one of the legs (shorter sides of the triangle) and "b" is the length of the other leg. "c" is the length of the hypotenuse.

a = y = 36.25cm

b = x = 20.93cm

a^2 + b^2 = c^2

(36.25)^2 + (20.93)^2 = c^2

1314.0625 + 438.0649 = c^2

√1752.1274 = √c^2

c = 41.8584209 ≈ 41.86

So your final answer is...

The length of the hypotenuse is about 41.86 cm.

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Hello! My name is Chris and I’ll be helping you with this problem.

Date: 9/27/20  Time:  9:23 pm CST

Answer:  

0.008

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The answer is "Option a".

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\to \bold{ \lim_{n \to \5}  \frac{(x^2+x-30)}{(x-5)} =  \lim_{n \to \5} (x+6) }\\\\

\to \lim_{n \to \5}  \frac{(x^2+(6-5)x-30)}{(x-5)} =  \lim_{n \to \5} (x+6) \\\\\to  \lim_{n \to \5}  \frac{(x^2+6x-5x-30)}{(x-5)} =  \lim_{n \to \5} (x+6) \\\\\to  \lim_{n \to \5}  \frac{x(x+6)-5(x+6)}{(x-5)} =  \lim_{n \to \5} (x+6) \\\\\to  \lim_{n \to \5}  \frac{(x+6) (x-5)}{(x-5)} =  \lim_{n \to \5} (x+6) \\\\\to  \lim_{n \to \5}  (x+6)  =  \lim_{n \to \5} (x+6) \\\\\to 5+6 =5+6\\\\\to 11 =11

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Step-by-step explanation:

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The radius r is 28 cm.

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The perimeter of the quadrant with radius 28 cm is approximately 99.98 cm.

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