The test statistic and p-value of the given data are 6.274 and 0.0001 respectively.
<h3>Test Statistic</h3>
The test statistic can be calculated using the formula below
![t = \frac{x-\mu}{\sigma / \sqrt{n} }](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%20%2F%20%5Csqrt%7Bn%7D%20%7D)
Solving for the mean and standard deviation, we can substitute the values into the above equation which will be
![t = \frac{x-\mu}{\sigma / \sqrt{n} } = 6.274](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%20%2F%20%5Csqrt%7Bn%7D%20%7D%20%3D%206.274)
<h3>P-Value</h3>
Using the data from the test statistic, we can calculate the p-value of the data
![p-value = p(z < 6.274)= 0.0001 = 0.00](https://tex.z-dn.net/?f=p-value%20%3D%20p%28z%20%3C%206.274%29%3D%200.0001%20%3D%200.00)
From the calculation above, the test statistic and p-value of the given data are
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brainly.com/question/4621112
Answer: 36
Step-by-step explanation:
One roll is of length = 9 feet
1 foot = 12 inches
9 feet = 12 *9 = 108 inches
Since there are 5 rolls
So, total length of 5 rolls = 108 * 5 = 540 inches
Since we are given that A seamstress needs to cut 15-inch pieces of ribbon from a roll of ribbon that is 9 feet in length.
We are supposed to find . What is the greatest number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon
So, number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon:
Hence the greatest number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon is 36
Answer:
x = 3(6 + y)/2
Step-by-step explanation:
Solving for x
Add 3y to both sides.
2x = 18 + 3y
Divide both sides by 2.
x = 18 + 3y/2
Factor out the common term 3.
x = 3(6 + y)/2
O think it is c subtracting 6 because adding and subtracting is the same so it’s either c or d