Answer:
3.384364 time 10^24 atoms
Explanation:
multiply by avogadro's number
The mass of NaN3 needed to produce 17.2 L nitrogen at STP is calculated as follows
find the moles of N2 produced at STP
At STP 1mole of gas = 22.4 L , what about 17.2 L of nitrogen
by cross multiplication
= (1 mole x17.2 L)/ 22.4 L= 0.768 moles
2NaN3 =2Na +3 N2
by use of mole ratio between NaN3 to N2 (2:3) the moles of NaN3 = 0.768 x2/3 = 0.512 moles of NaN3
mass of NaN3 is therefore =moles of NaN3 xmolar mass of NaN3
=0.512moles x 65 g/mol =33.28 grams of NaN3
Depends on what your question I currently have a 99 in there
Answer:
368.92g
Explanation:
Firstly, let's balance the equation which is
2NO + O₂ ---> 2NO₂
Starting with 8.02 mol of NO let's calculate the moles of oxygen which is in a 2 : 1 molar ratio
2NO + O₂
2 : 1
8.02 mol : x mol
Moles of O₂ = 8.02 ÷ 2 = 4.01 mol
Doing the same thing for 18.75 mol of O₂ to calculate the number of moles of NO
2NO + O₂
2 : 1
x mol : 18.75 mol
Moles of NO = 18.75 × 2 = 37.5 however we are told we have 8.02 moles of NO, so we are unable to use 18.75 mol of O₂
Using 8.02 mol of NO to figure out the number of moles of NO₂ :
2NO : 2NO₂
They have the same molar ratio of 2 : 2, so the number of moles is 8.02
Using formula moles = mass / Molar mass
Rearranging to find mass = moles × molar mass
Molar mass of NO₂ = 14 + 16 + 16 = 46
Mass = 46 × 8.02 = 368.92g
