Answer: The enthalpy of the given reaction is 1234.8kJ/mol.
Explanation: Enthalpy change of the reaction is the amount of heat released or absorbed in a given chemical reaction.
Mathematically,
For the given reaction:
![\Delta H_{rxn}=\Delta H_f_{(C_2H_5OH)}+3\Delta H_f_{(O_2)}-[2\Delta H_f_{(CO_2)}+3\Delta H_f_{(H_2O)}]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5CDelta%20H_f_%7B%28C_2H_5OH%29%7D%2B3%5CDelta%20H_f_%7B%28O_2%29%7D-%5B2%5CDelta%20H_f_%7B%28CO_2%29%7D%2B3%5CDelta%20H_f_%7B%28H_2O%29%7D%5D)
Putting values in above equation, we get:
![\Delta H_{rxn}=[-277.6+3(0)]-[2(-393.5)+3(-241.8)]kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B-277.6%2B3%280%29%5D-%5B2%28-393.5%29%2B3%28-241.8%29%5DkJ%2Fmol)
The answer is 84.00661 grams
Answer:
Zinc is Zn and Magnesium is Mg
Answer:
The answer to your question is 34 g of H₂O₂
Explanation:
Data
mass of H₂O₂ = ?
mass of O₂ = 32 g
Process
1.- Write the balanced chemical reaction
H₂O₂ ⇒ H₂ + O₂
2.- Calculate the molar mass of H₂O₂ and O₂
Molar mass H₂O₂ = (1 x 2) + (16 x 2) = 34 g
Molar mass of O₂ = 2 x 16 = 32 g
3.- Use proportions to calculate the mass of O₂
34g of H₂O₂ -------------- 32g of O₂
x -------------- 32g of O₂
x = (32 x 34) / 32
x = 34 g of H₂O₂
