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2 years ago

What is it called when an enzyme changes shape

Chemistry

1 answer:

7nadin3 [17]2 years ago

4 0

Answer: Induced Fit

Explanation: The process wherein the enzymes change their shape is called as induced fit. It is the precision aligning of enzymes essential for catalytic activity which is caused by the binding of the substrate as enzymes possess active sites. Hence, as the substrate approaches the enzymes, the enzyme alters its shape.

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How many grams of lithium are in 6.02*10^21 atoms

valentinak56 [21]

the answer is 0.0693769. 6.02x10^21 x6.94/ 6.022x10^23 is the formua you would use.

7 0

4 years ago

Caffeine, a molecule found in coffee, tea, and certain soft drinks, contains C, H, O, and N. Combustion of 10.0 g of caffeine pr

denis-greek [22]

Answer:

194 g/mol.

Explanation:

Hello,

In this case, one first must compute the mass of each element as shown below:

$C=18.13gCO_2*\frac{12gC}{44gCO_2} =4.945gC\\H=4.639gH_2O*\frac{2.016gH}{18.0152gH_2O}=0.519gH\\N=2.885gN_2\\O=10.0g-4.945g-0.519g-2.885g=1.651gO$

Next, the corresponding moles:

$C=4.945gC*\frac{1molC}{12gC}=0.412mol\\H=0.519gH*\frac{1molH}{1gH}=0.519mol\\N=2.885gN*\frac{1molN}{14gN}=0.206molN\\O=1.648gO*\frac{1molO}{16gO} =0.103molO$

Then, each element's subscripts is found to be:

$C=\frac{0.412}{0.103}=4\\H=\frac{0.519}{0.103}=5\\N=\frac{0.206}{0.103} =2\\O=\frac{0.103}{0.103}=1$

Therefore, the empirical formula is:

$C_4H_5N_2O$

Nonetheless, it has a molar mass of 97bg/mol, thereby, by multiplying such formula by 2 one gets:

$C_8H_10N_4O_2$

Which has a molar mass of 194 g/mol being correctly contained in the given interval.

Best regards.

8 0

3 years ago

Show all calulations

Black_prince [1.1K]

Im confused here. Add the rest of the question for me to help you

5 0

2 years ago

Assuming your weight is 440.55 N and the force of gravity on Earth is 9.8 m/s2 what is your mass? *

Alexandra [31]

Answer:

44.95408163 kg

44.95 kg (2 decimal places)

Explanation:

Weight=Mass*Gravity

440.55=m*9.8

Make m the subject

M=440.55/9.8

M= 44.95 kg

5 0

4 years ago

If 3 g of element C combine with 8 g of element D to form compound CD, how many grams of D are needed to form compound CD2?

bija089 [108]

<span>For the answer to the question above,
If 3g of element combines with 8g of D to form CD it means
1 mole of C = 3g
1 mole of D = 8g
hence it forms CD.
So to form CD2 you need 16g of element D
I hope my answer helped you</span>

8 0

3 years ago