Answer:
The probability that an athlete chosen is either a football player or a basketball player is 56%.
Step-by-step explanation:
Let the athletes which are Football player be 'A'
Let the athletes which are Basket ball player be 'B'
Given:
Football players (A) = 13%
Basketball players (B) = 52%
Both football and basket ball players = 9%
We need to find probability that an athlete chosen is either a football player or a basketball player.
Solution:
The probability that athlete is a football player = 
The probability that athlete is a basketball player = 
The probability that athlete is both basket ball player and football player = 
We have to find the probability that an athlete chosen is either a football player or a basketball player
.
Now we know that;

Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.
Answer: 72 over 7
Step-by-step explanation: Hoped this helped you
Answer:
y = s * 4
Step-by-step explanation:
You multiplied 4 to 3 to obtain 12:
x = 3 ; x = 3 * 4 ; x = 12
Therefore, if you multiply 4 to x, you must do the same to the other:
y = s
y = s * 4 is your answer.
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Answer: 0.0083
0.00083
0.000083
Step-by-step explanation: hope it helps
Answer:
Angle 1 =51. 72+57=129. 129+51=180
Angle 2=18. there is a right angle 72+18=90
Angle 3=123
Angle 4=39 angle 2+angle 3+angle 4 equals 180
123+18=141
180-141=39