No. A polynomial equation in one variablel ooks like P(x) = Q(x), where P and Q are polynomials.
Consider polynomial equations x^2 = 3 and x^2 = 1.
Obviously they have real solutions.
Subtract the two polynomial equations:
(x^2 - x^2) = (3 - 1)
0 = 2...
We get the polynomial equation 0 = 2. We call this a polynomial equation because single constants are also by definition polynomials.
Obviously 0 = 2 has no real solution.
Answer:
Step-by-step explanation:
We are given the slope along with an (x, y) coordinate with which to write the equation. You could use this info in the slope-intercept form and solve for b, or you could use this info in the point-slope form and solve it for y. Trust me when I tell you that either one will get you the correct equation. Promise! I used the point-slope form, just because. ; )
y - 2 = 3(x - 1) and
y - 2 = 3x - 3 and
y = 3x - 1 OR in standard form, we will put the x and y terms on the same side of the equals sign, separated from the constant:
-3x + y = -1. But if we get picky and do not like to lead with negatives, we could change ALL the signs to their opposites (which is the same as multiplying the whole thing by a -1) to get
3x - y = 1 which is the third choice down.
Answer:
Students deliver catalogues and leaflets to houses.
One day, they have to deliver 480 catalogues and 1520 leaflets.
Each student can deliver either 15 catalogues or 80 leaflets in 1 hour. Each student can only work for 8 hours. All students hired are paid £50.40 per day, even if they don't work a full day.
If the minimum number of students are hired, how much will the wage bill be?
Because we're given two points on the line, we can apply the slope formula to find the answer:
-4 - 8 / 2 - (-1)
-12 / 3
-4
<h3>The slope of the line is -4.</h3>
Draw whats on the paper, thats your answer
