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tankabanditka [31]
3 years ago
9

The large Ferris wheel makes a revolution in 60 seconds. The small Ferris wheel makes one revolution in 20 seconds. How many sec

onds will pass before Jeremy and Deborah are both at the bottom again?
Mathematics
1 answer:
Wewaii [24]3 years ago
4 0

Answer:

120 seconds

Step-by-step explanation:

60         20

120        40

180       60

            80

            100

            120

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Find the length of the short leg of a 30-60-90 triangle if the long leg is 3cm
antoniya [11.8K]

Answer:

Short leg = √3 cm

Step-by-step explanation:

the opposite angle of long leg is 60°

hypotenuse : x

sin 60° = 3/x = √3 / 2

x = (3 x 2) / √3 = 2√3

short leg length (s)

Cos 60° = 1/2 = s / x = s / 2√3

s = √3

7 0
3 years ago
Find three consecutive odd integers so that the sum of twice the first, the second
netineya [11]

Answer: 23, 25, 27

Step-by-step explanation:

Let the 3 consecutive odd numbers be x, x+2 and x+4.

So

2x+(x+2)+3(x+4)=152

2x + x + 2 + 3x + 12 = 152

6x+14=152

6x = 152 - 14

x=138/6

x=23

So, the numbers are 23, 25 and 27.

7 0
3 years ago
Measurements of atoms, such as amounts, distances, and weights, are often very large or very small when compared to measurements
Ainat [17]

Answer:

Step-by-step explanation:

1)3.8 *10¹⁵

2)4.0*10¹⁴

3)30.4*10⁻²⁰

4)523,000,000,000 atoms

5)0.000 000 000 000 000 000 000 000 00167

7 0
2 years ago
You make dog
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Answer:

well it depends on how many collars you have, and if there is an image you should attach it to the question

5 0
3 years ago
The number of people in a car that crosses a certain bridge is represented by the random variable X, which has a mean value μX =
Alona [7]

Let Y be the total amount of money paid by any given set of passengers. If there are X passengers in a car, then the driver must pay a toll of Y=0.5X+3.

Then Y has first moment (equal to the mean)

E[Y]=E[0.5X+3]=0.5E[X]+3E[1]=0.5\mu_X+3=\boxed{4.35}

and second moment

E[Y^2]=E[0.25X^2+3X+9]=0.25E[X^2]+3E[X]+9E[1]=0.25E[X^2]+3\mu_X+9

Recall that the variance is the difference between the first two moments:

\mathrm{Var}[X]=E[X^2]-E[X]^2\implies E[X^2]={\sigma^2}_X+{\mu_X}^2

\implies E[Y^2]=0.25({\sigma^2}_X+{\mu_X}^2)+3\mu_X+9\approx19.22

\implies\mathrm{Var}[Y]=E[Y^2]-E[Y]^2=\boxed{0.3}

3 0
3 years ago
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