Hi!
1/4 of 20 pencils are 5 pencils.
Since he gave away 4 pencils,
Total = 5 + 4 = 9
Mr. Simms use and give away total 9 pencils.
Answer:
g'(0) = 0
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Pre-Calculus</u>
<u>Calculus</u>
- Derivatives
- Derivative Notation
- The derivative of a constant is equal to 0
- Derivative Property:
![\frac{d}{dx} [cf(x)] = c \cdot f'(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcf%28x%29%5D%20%3D%20c%20%5Ccdot%20f%27%28x%29)
- Trig Derivative:
![\frac{d}{dx} [cos(x)] = -sin(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcos%28x%29%5D%20%3D%20-sin%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
g(x) = 8 - 10cos(x)
x = 0
<u>Step 2: Differentiate</u>
- Differentiate [Trig]: g'(x) = 0 - 10[-sin(x)]
- Simplify Derivative: g'(x) = 10sin(x)
<u>Step 3: Evaluate</u>
- Substitute in <em>x</em>: g'(0) = 10sin(0)
- Evaluate Trig: g'(0) = 10(0)
- Multiply: g'(0) = 0
Answer:
see graph of y = 5x - 7
Step-by-step explanation:
If graphing is the task, you should rewrite the equation in a y = ax + b form. All straight lines can be described in this form, only the a and b determine which line it is.
Your equation 5x-y=7 has the 5x on the left side, so lets move it to the right. It will get a negative sign (this is the same as subtracting 5x like you did in your picture)
5x - y = 7
-y = 7 - 5x
Now we still have the -y which should be a +y. So we multiply left and right with -1 and get:
y = -7 + 5x
If we swap the -y and 5x (we can, because they are just an addition), we get:
y = 5x - 7
Now the equation is in its "normal" form. It's like the y = ax + b with a and b chosen as a=5 and b=-7.
The normal form is handy because you can immediately see the slope is 5 and the intersection with the y-axis is at y=-7.