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IRISSAK [1]
3 years ago
10

Which of these represents a quadratic polynomial with exactly two zeros given by - 21 and 2i?

Mathematics
2 answers:
weqwewe [10]3 years ago
8 0

Answer:

B. x² + 4

Step-by-step explanation:

(0+/-√-16)2

+/- 4i / 2

+/- 2i

spin [16.1K]3 years ago
8 0

Answer:

B

Step-by-step explanation:

(x + 2i)(x - 2i)

= x² - 2ix + 2ix - (2i)²

= x² - 4i²

= x² -4(-1)

= x² + 4

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Write an expression for the following situation and solve it. Mr. Simms bought 20 pencils. He used 1/4 of the pencils and then g
Nitella [24]
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1/4 of 20 pencils are 5 pencils.
Since he gave away 4 pencils,
Total = 5 + 4 = 9
Mr. Simms use and give away total 9 pencils.
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3 years ago
Value of the derivative of g(x)=8-10Cosx at 'x=0' is?
VLD [36.1K]

Answer:

g'(0) = 0

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

<u>Pre-Calculus</u>

  • Unit Circle

<u>Calculus</u>

  • Derivatives
  • Derivative Notation
  • The derivative of a constant is equal to 0
  • Derivative Property: \frac{d}{dx} [cf(x)] = c \cdot f'(x)
  • Trig Derivative: \frac{d}{dx} [cos(x)] = -sin(x)

Step-by-step explanation:

<u>Step 1: Define</u>

g(x) = 8 - 10cos(x)

x = 0

<u>Step 2: Differentiate</u>

  1. Differentiate [Trig]:                    g'(x) = 0 - 10[-sin(x)]
  2. Simplify Derivative:                   g'(x) = 10sin(x)

<u>Step 3: Evaluate</u>

  1. Substitute in <em>x</em>:                    g'(0) = 10sin(0)
  2. Evaluate Trig:                      g'(0) = 10(0)
  3. Multiply:                               g'(0) = 0
3 0
3 years ago
5x-y=7
seropon [69]

Answer:

see graph of y = 5x - 7

Step-by-step explanation:

If graphing is the task, you should rewrite the equation in a y = ax + b form. All straight lines can be described in this form, only the a and b determine which line it is.

Your equation 5x-y=7 has the 5x on the left side, so lets move it to the right. It will get a negative sign (this is the same as subtracting 5x like you did in your picture)

5x - y = 7

-y = 7 - 5x

Now we still have the -y which should be a +y. So we multiply left and right with -1 and get:

y = -7 + 5x

If we swap the -y and 5x (we can, because they are just an addition), we get:

y = 5x - 7

Now the equation is in its "normal" form. It's like the y = ax + b with a and b chosen as a=5 and b=-7.

The normal form is handy because you can immediately see the slope is 5 and the intersection with the y-axis is at y=-7.

3 0
3 years ago
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