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zloy xaker [14]
3 years ago
7

What is this question2/3×=1/6​

Mathematics
1 answer:
pickupchik [31]3 years ago
3 0
X is 1/4
2/3 X 1/4 = 1/6 make all have the same bottom number to make it easier

8/12 x 3/12 = 2/12
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There are 3 white balls, 7 red balls, and 5 green balls in a container. A ball is chosen at random. What is the probability of c
Kisachek [45]

Answer:

(p green) 1/3

(p red) = 1/2

Step-by-step explanation:

Add the number of balls together to get the total.

3 + 7 + 5 = 15

Find the probability of choosing green.

(p green) = 5/15

reduce by 5

(p green) 1/3

Since you kept the green ball, there are now a total of 14 balls.

Find the probability of choosing red.

(p red) = 7/14

reduce by 7

(p red) = 1/2

7 0
2 years ago
Find the probability for the experiment of tossing a coin three times. Use the sample space S = {HHH, HHT, HTH, HTT, THH, THT, T
myrzilka [38]

Answer:

1) 0.375

2) 0.375

3) 0.5

4) 0.5

5) 0.875

6) 0.5                          

Step-by-step explanation:

We are given the following in the question:

Sample space, S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

1. The probability of getting exactly one tail

P(Exactly one tail)

Favorable outcomes ={HHT, HTH, THH}

\text{P(Exactly one tail)} = \dfrac{3}{8} = 0.375

2. The probability of getting exactly two tails

P(Exactly two tail)

Favorable outcomes ={ HTT,THT, TTH}

\text{P(Exactly two tail)} = \dfrac{3}{8} = 0.375

3. The probability of getting a head on the first toss

P(head on the first toss)

Favorable outcomes ={HHH, HHT, HTH, HTT}

\text{P(head on the first toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

4. The probability of getting a tail on the last toss

P(tail on the last toss)

Favorable outcomes ={HHT,HTT,THT,TTT}

\text{P(tail on the last toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

5. The probability of getting at least one head

P(at least one head)

Favorable outcomes ={HHH, HHT, HTH, HTT, THH, THT, TTH}

\text{P(at least one head)} = \dfrac{7}{8} = 0.875

6. The probability of getting at least two heads

P(Exactly one tail)

Favorable outcomes ={HHH, HHT, HTH,THH}

\text{P(Exactly one tail)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

3 0
3 years ago
Please look at the picture and answer it thank you.
yulyashka [42]
<h3>Answer :- </h3>

  • 15

<h3>Solution :- </h3>

  • 8x + 14 + 42 = 180
  • 8x + 56 = 180
  • 8x = 180 - 56
  • 8x = 124
  • x = 124/8
  • x = 15

8 0
2 years ago
Read 2 more answers
Ignore the fact that one of the answer choices are orange, but what is the correct answer to this, let me know ASAP
Alex Ar [27]

Answer:

haha it's actually the orange one 225cm^{3}

Step-by-step explanation:

Hope this helps :)

8 0
3 years ago
Read 2 more answers
If a scale factor of 1/5
Artist 52 [7]
Hope this is what’s you where looking for

5 0
3 years ago
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