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3 years ago

7

Answer correctly

2 answers:

lara31 [8.8K]3 years ago

7 0

6w-10 represents the total amount of fence will need to complete the rectangle of fence in his yard. The fence will need two lengths and 2 widths to complete the rectangle. If the width is w, and the length is 2w-5, then the total for the rectangle would be w+w+2w-5+2w-5 which simplifies to 6w-10.

Vaselesa [24]3 years ago

3 0

Answer:

6w - 10 represents the length of the fence

Step-by-step explanation:

If the width was w, then the length of the rectangular fencing would be 2w - 5 as he wants it 5 feet less than twice the width. So the total perimeter of the fencing would be w + w + 2w - 5 + 2w - 5 = 6w - 10

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Answer:

First, find the area of the surface of the shed. Two walls will have an area of 14 x 8 and two walls will have an area of 18 x 10. We get the equation 2(14x8) + 2(10x8) = 224 + 160 = 384 square feet

Next, divide the square footage of the shed's surface by 250 to find how many gallons of paint are needed. 384/250 = 1.54 gallons of paint (rounded to the nearest hundredth)

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2 years ago

A cylinder has a volume of 360 cubic centimeters. Find the volume of a cone with the same height and diameter as the cylinder.

ratelena [41]

The formula of a volume of a cylinder:

$V_{cylinder}=\pi r^2H$

The formula of a volume of a cone:

$V_{cone}=\dfrac{1}{3}\pi r^2H$

If a cone and a cylinder have the same radius and the same height, then a volume of a cylinder is three times greater than a volume of a cone.

$V_{cylinder}=3V_{cone}\\\\V_{cone}=\dfrac{1}{3}V_{cylinder}$

$V_{cylinder}=360\ cm^3$

$V_{cone}=\dfrac{1}{3}\cdot360\ cm^3=120\ cm^3$

<h3>Answer: The volume of a cone is equal 120 cm³.</h3>

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3 years ago

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andreyandreev [35.5K]

Math Xl I Know A Website That You Can Get All Answer For Math Xl

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2 years ago

I need help with this problem y=5x-3

defon

Answer:

Slope= 5

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Step-by-step explanation:

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2 years ago

Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

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2 years ago