Eliminate x's
multiply 2nd equation by -2 ad add to first
2x+3y=9
<u>-2x-10y=-16 +</u>
0x-7y=-7
-7y=-7
divide by -7
y=1
sub back
2x+3y=9
2x+3(1)=9
2x+3=9
minus 3
2x=6
divide 2
x=3
x=3
y=1
(x,y)
(3,1)
D
Answer: 90 degrees clockwise
Step-by-step explanation:
The co ordinates of P' is (-7,-2) and Q' is (-16, -8)
<u><em>Explanation</em></u>
PQ is rotated 180 degrees clockwise about P. It means <u>P and P' are the same points</u>.
According to the graph, the coordinates of P is (-7, -2) and Q is (2, 4)
When PQ is rotated 180 degrees clockwise about P, then <u>P or P' will be the mid-point of Q and Q' </u>
Suppose, the co ordinate of Q' is (x, y)
Now according to the mid-point formula, the coordinate of P or P' will be: 
, which is actually at (-7, -2)
Thus.....
So, the co ordinates of P' is (-7,-2) and Q' is (-16, -8)
Answer:
5^4
Step-by-step explanation:
i hope this helps :)
Answer:
11.33 * 16.33 meters to the nearest hundredth.
Step-by-step explanation:
Let the width of the pool be x meters, then the length is x+5 meters.
The length of whole area = x + 5 + 2(3) = x + 11 meters and the width is
x + 2(3) = x + 6 meters.
So we have the equation (x + 6)(x + 11) = 387.
x^2 + 17x + 66 = 387
x^2 + 17x - 321 = 0
x = [-17 +/- sqrt (17^2 - 4*1*-321)] / 2
x = 11.33 meters
So the width is 11.3 m and the length is 16.33 meters.
