Write a story problem that includes both integers - 8 and 12

Mathematics

1 answer:

Vadim26 [7]3 years ago

7 0

I had 12 pencils my friend took 8 how many do I have now

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Which of the following is equivalent to (5)^7/3

kifflom [539]

The answer is $\sqrt[3]{ 5^{7} }$ 

The reason we get this answer is because when you are converting from exponential form, to radical form you always place the numerator as our constant's exponent in the radical ( $5^{7}$ is called the radicand because it is located in the radical) and the denominator in front of the radical, where it would be called the index.

Here's what a formula would look like: $( \sqrt[n]{x} ) ^{q}=x^{ \frac{p}{q} }$

Thank you for your question! I hope this helped! Have an amazing day and feel free to let me know if I can help you further! :D

3 0

2 years ago

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What two numbers add to 8 and multiply to 28

anygoal [31]

Find numbers that multiply to 28 and add them to see if they add to 8
28=
1 and 28=29 not 8
2 and 14=16 not 8
4 and 7=11 not 8
that's it'
no 2 numbers
we must use quadratic formula

x+y=8
xy=28

x+y=8
subtract x fromb oths ides
y=8-x
subsitute
x(8-x)=28
distribute
8x-x^2=28
add x^2 to both sides
8x=28+x^2
subtract 8x
x^2-8x+28=0

if you have
ax^2+bx+c=0 then x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$
so if we have
1x^2-8+28=0 then
a=1
b=-8
c=28

x= $\frac{-(-8)+/- \sqrt{(-8)^{2}-4(1)(28)} }{2(1)}$
x= $\frac{8+/- \sqrt{-48} }{2}$
x= $\frac{8+/- 4 \sqrt{-3} }{2}$
x= $4+/- 2 \sqrt{-3}$
x= $4+/- 2i \sqrt{3}$
there are no real numbers that satisfy this

5 0

3 years ago

Choose the correct steps to graph the slope of -2/5

notka56 [123]

Answer:

A) 2 down, 5 right

Step-by-step explanation:

hope this helpss

8 0

2 years ago

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Solve the system by substitution. x – 3y = 4 2x – 6y = 8 A. no solution B. x = 4, y = 0 C. x = 0, y = 0 D. infinite solutions