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Anna11 [10]
3 years ago
10

A baby weighed 7.25 at birth. at the end of 8 month,the baby weighed 2 1/2 times its birth weight. how many pounds did the baby

weigh at the end of 8 months
Mathematics
1 answer:
Artyom0805 [142]3 years ago
4 0
2 1/2 is in mixed fraction. So let's first make it into improper fraction.

(2*2 + 1) / 2 = 5/2

5/2 of 7.25 = (5*7.25) / 2 = 18.125 

in short, 18.125 is the answer

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Please help <br><br> 4(1 - p) = -4p + 4
erica [24]

4-p=-4p+4

4-p+4p-4

3p

Step-by-step explanation:

that iw the answer

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2 years ago
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there is a ratio of 5 girls to 3 boys in the chorus.there are 24 boys in the chorus.how many girls are there
pshichka [43]

I think that the answer to this is 40 girls  

24/3=8

8*5=40

hope this helps

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The lines graphed below are perpendicular. The slope of the redline is -2. What is the slope of the green line
attashe74 [19]

Answer:

It would be undefined if the line is vertical.

Step-by-step explanation:

6 0
3 years ago
I don’t understand how this question
Vladimir79 [104]

Answer:

<u>x = √51</u>

Step-by-step explanation:

The given figure is a <u>right triangle</u>.

<u>Using the Pythagorean Theorem to find x</u>

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4 0
2 years ago
The scores on the LSAT are approximately normal with mean of 150.7 and standard deviation of 10.2. (Source: www.lsat.org.) Queen
faltersainse [42]

Answer:

a=150.7 -0.385*10.2=146.773

So the value of height that separates the bottom 35% of data from the top 65% (Or the 35 percentile) is 146.7.  

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the  scores on the LSAT of a population, and for this case we know the distribution for X is given by:

X \sim N(150.7,10.2)  

Where \mu=150.7 and \sigma=10.2

We want to find a value a, such that we satisfy this condition:

P(X>a)=0.65   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.35 of the area on the left and 0.65 of the area on the right it's z=-0.385. On this case P(Z<-0.385)=0.35 and P(Z>-0.385)=0.65

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

Z=-0.385

And if we solve for a we got

a=150.7 -0.385*10.2=146.773

So the value of height that separates the bottom 35% of data from the top 65% (Or the 35 percentile) is 146.7.  

5 0
3 years ago
Read 2 more answers
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