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astraxan [27]
3 years ago
13

Lila is building a slide for her kids. The ladder is 3 meters tall and the slide is 5 meters long. What is the distance between

the ladder and the bottom of the slide?
Mathematics
1 answer:
lisov135 [29]3 years ago
7 0

Answer:

Step-by-step explanation: For a problem like this, it’s best to use Pythagorean Theorem which is a^2+b^2=c^2 .

In this problem they gave us a and c already so we are trying to find b.

3^2+?=5^2

9+?=25

25-9=16

Find the square root of 16 which is 4

Answer: The distance between the ladder and the slide is 4 meters

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Answer:

\displaystyle \frac{dA}{dt} = 102 \ m^2/day

General Formulas and Concepts:

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Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle l = 10 \ meters<u />

<u />\displaystyle \frac{dl}{dt} = 4 \ m/day<u />

<u />\displaystyle w = 23 \ meters<u />

<u />\displaystyle \frac{dw}{dt} = 1 \ m/day<u />

<u />

<u>Step 2: Differentiate</u>

  1. [Area of Rectangle] Product Rule:                                                                 \displaystyle \frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}

<u>Step 3: Solve</u>

  1. [Rate] Substitute in variables [Derivative]:                                                    \displaystyle \frac{dA}{dt} = (10 \ m)(1 \ m/day) + (23 \ m)(4 \ m/day)
  2. [Rate] Multiply:                                                                                                \displaystyle \frac{dA}{dt} = 10 \ m^2/day + 92 \ m^2/day
  3. [Rate] Add:                                                                                                      \displaystyle \frac{dA}{dt} = 102 \ m^2/day

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Implicit Differentiation

Book: College Calculus 10e

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