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Elza [17]
2 years ago
15

PLZ HELP FAST (multiple choice)​

Mathematics
2 answers:
Nataly_w [17]2 years ago
8 0
The answer is 0 (my sentence needs to have 20 characters so I’m typing extra)
never [62]2 years ago
6 0

Answer:

C. 0

Step-by-step explanation: I think if i am wrong im sorry

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A school P is 16km due west of a school Q. what is the bearing of Q from P​
Irina-Kira [14]

Answer:

16Km due east of school P

Step-by-step explanation:

Given

A school P is 16km due west of a school Q

Thus, we can say that distance PQ = 16 km.

________________________________

now we have to find  the bearing of Q from P​

As distance is same

distance PQ = distance QP

Thus,

Distance will remain same of 16 km.

For direction,

If Q is west of P, then P will be east of QP------------------>Q

as shown in figure P is west of Q,

now from point P , Q is west P.

Thus,

Bearing of  School Q from P is 16Km due east of school P

7 0
3 years ago
HELP ME PLS<br> Write the ratio<br> 3/8 with a numerator of 9.
Anna35 [415]

Answer:

24

Step-by-step explanation:

3    9

8    

9 times 8

divided by 3 = denominator

9x8÷3=24

7 0
3 years ago
Read 2 more answers
Suppose two angles in a coordinate plane, one measuring 80° and the other measuring 160°, were both rotated 180° about the origi
Snowcat [4.5K]
C because I just took it
5 0
2 years ago
Read 2 more answers
Find each Of change. Round to the nearest whole percent if necessary. State whether the percent Of change is an increase or 1. O
Alenkasestr [34]

Answer:

1. The percentage change is 74% and it is a percentage decrease

2. The percentage change is 15% and it is a percentage decrease

3. The percentage change is 20% and it is a percentage decrease

4. The percentage change is 43% and it is a percentage increase

5. The percentage change is 40% and it is a percentage decrease

6. The percentage change is 39% and it is a percentage decrease

Step-by-step explanation:

Given

1.\ Original = 5; New = 1.3

2.\ Original = 160; New = 136

3.\ Original = 15; New = 12

4.\ Original = 7; New = 10

5.\ Original = $30; New = $18

6.\ Original = 9.6; New = 5.9

Required

Determine the percentage change and state whether it's an increase or decrease

Percentage change is calculated as:

\%Change = \frac{New - Original}{Original} * 100\%

1.\ Original = 5; New = 1.3

\%Change = \frac{1.3 - 5}{1.3} * 100\%

\%Change = \frac{-3.7}5} * 100\%

\%Change = \frac{-3.7 * 100\%}{5}

\%Change = \frac{-370\%}{5}

\%Change = -74\%

<em>The percentage change is 74% and it is a percentage decrease</em>

2.\ Original = 160; New = 136

\%Change = \frac{136 - 160}{160} * 100\%

\%Change = \frac{-24}{160} * 100\%

\%Change = \frac{-24 * 100\%}{160}

\%Change = \frac{-2400\%}{160}

\%Change = -15\%

<em>The percentage change is 15% and it is a percentage decrease</em>

3.\ Original = 15; New = 12

\%Change = \frac{12- 15}{15} * 100\%

\%Change = \frac{-3}{15} * 100\%

\%Change = \frac{-3* 100\%}{15}

\%Change = \frac{-300\%}{15}

\%Change = -20\%

<em>The percentage change is 20% and it is a percentage decrease</em>

4.\ Original = 7; New = 10

\%Change = \frac{10- 7}{7} * 100\%

\%Change = \frac{3}{7} * 100\%

\%Change = \frac{3* 100\%}{7}

\%Change = \frac{300\%}{7}

\%Change = 43\% -- (approximated)

<em>The percentage change is 43% and it is a percentage increase</em>

<em></em>

5.\ Original = $30; New = $18

\%Change = \frac{18- 30}{30} * 100\%

\%Change = \frac{-12}{30} * 100\%

\%Change = \frac{-12* 100\%}{30}

\%Change = \frac{-1200\%}{30}

\%Change = -40\%}

<em>The percentage change is 40% and it is a percentage decrease</em>

6.\ Original = 9.6; New = 5.9

\%Change = \frac{5.9- 9.6}{9.6} * 100\%

\%Change = \frac{-3.7}{9.6} * 100\%

\%Change = \frac{-3.7* 100\%}{9.6}

\%Change = \frac{-370\%}{9.6}

\%Change = -39\% -- (approximated)

<em>The percentage change is 39% and it is a percentage decrease</em>

5 0
3 years ago
A person jogged 10 times along the perimeter of a rectangular field at the rate of 12 kilometers per hour for 30 minutes. If the
notsponge [240]

Answer:

<u>The area of the rectangular field is 20,000 square meters.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Number of times a person jogged along the rectangular field = 10

Speed of the person jogging = 12 km per hour

Time he/she jogged = 30 minutes = 0.5 hours

Length of the field = twice its width

2. Find the area of the field in square meters.

Step A: Let's calculate the distance the person jogged

Let's recall the formula of the speed:

Speed = Distance/Time

Distance = Speed * Time

Replacing with the values we know:

Distance = 12 * 0.5

<u>Distance = 6 kilometers</u>

Step B: Let's calculate the perimeter of the rectangular field

Distance jogged = ¨Perimeter * 10

6 kilometers = Perimeter * 10

Perimeter = 6/10

<u>Perimeter = 0.6 kilometers = 0.6 * 1,000 = 600 meters</u>

Perimeter = 2 * Length + 2 * Width

x = Width of the rectangular field

2x = Length of the rectangular field

600 = 2 * 2x + 2 * x

600 = 4x + 2x

600 = 6x

<u>x = 600/6 = 100 meters ⇒ 2x = 200 meters</u>

Step C: Let's calculate the area of the rectangular field

Let's recall the formula of the area of a rectangle:

A = Length * Width

A = 200 * 100

<u>A = 20,000 m² (square meters)</u>

7 0
3 years ago
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