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Vinil7 [7]
3 years ago
6

Vivian is making keychains with beads she wants each keychain to have the same number of beads she has 12 blue beads and 21 yell

ow beads what is the greatest number of key chains she can make with exactly the same
Mathematics
2 answers:
igor_vitrenko [27]3 years ago
8 0
11 key chains and 3 beads each. Just do greatest common factor if that helps any. <3
Semmy [17]3 years ago
3 0
11 key chains with 3 beads each
You might be interested in
Solve for h.<br> A=3h <br> Can anyone help me?
IgorC [24]

Answer:

h = 3/A

Step-by-step explanation:

A = 3h

Divide both sides by 3 to isolate h:

A/3 = 3h/3

Simplify and get

A/3 = h or h = A/3

Hope this helps!

8 0
2 years ago
The curved surface area of a right circular cylinder of height 14 cm is 88 cm2. find the diameter of the base of the cylinder​
White raven [17]

Answer:

2 cm

Step-by-step explanation:

h = 14 cm

Curved surface area of a right circular cylinder = 88 cm²

2πrh = 88

2 * \frac{22}{7}*r*14=88\\\\r = \frac{88*7}{2*22*14}\\\\ r =1 \\\\r = 1 cm

Diameter = 2 * r = 2 * 1 = 2  cm

6 0
3 years ago
John has dimes and quarters worth $4.50. He has four more quarters than dimes. How many coins of
N76 [4]

Answer:

10 dimes and 14 quarters

Step-by-step explanation:

take the amount of four quarters to start with: 1$

then from here, for add one quarter and one dimes worth: 35 c

keep adding until you reach 450

then count how many 35 c you counted and thats how many dimes you have

add four to that number and youll get the amount of quarters

5 0
2 years ago
Jessie has some nickels, dimes, and quarters in her bank. The number of coins is 26 . The expression 0.05⁢n+0.10⁢d+0.25⁢q repres
Westkost [7]
Use the substituting equation to solve
7 0
3 years ago
Find the length of the following​ two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 &lt; t &lt; 16
andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)}     dt

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)}     dt

Doing the operations inside of the brackets the derivatives are:

1 ) (\frac{d((1/2)t^2)}{dt} )^2= t^2

2) \frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1

Entering these values of the integral is

r(t)= \int\limits^{16}_{0}  \sqrt{t^2 +2t+1}     dt

It is possible to factorize the quadratic function and the integral can reduced as,

r(t)= \int\limits^{16}_{0} (t+1)  dt= \frac{t^2}{2} + t

Thus, evaluate from 0 to 16

\frac{16^2}{2} + 16

The value is r= 144 units

5 0
3 years ago
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