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3 years ago

Which shows the expression below in simplified form?

Mathematics

1 answer:

Kisachek [45]3 years ago

3 0

Answer: C. 3.2 × 10^4

Step-by-step explanation:

for this case the multiplication of the values with exponent are summed, as the exponent are the 6 and -3

6 - 3 = 3

this will be the exponent of the common value which is the 10.

after you only need to multiply 8 and 4 by separate the

8 * 4 = 32.

then we only need to place the values one by one

32 × 10^3

3 is the result of the sum of the exponent.

10 is the common value.

32 is the result of the product.

if we add another zero to the multiplication we get 3.2 and exponent finish with one more zero, then we get this result

3.2 × 10^4

because of that the C is the correct answer, keep in mind that the other answers do not apply correctly the rule of the exponent, because the rest of answer give us wrong answer with final result of the exponent.

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An online retailer employs 1,300 employees. One of their competitors would like to test the hypothesis that the average age of

Harrizon [31]

Answer:

Null hypothesis: $\mu \geq 36$

Alternative hypothesis: $\mu < 36$

$p_v =P(t_{21}$

Since the $p_v< \alpha$ we can reject the null hypothesis at 2.5 % of significance.

Step-by-step explanation:

Data given and notation

$\bar X=33.9$ represent the sample mean

$s=4.1$ represent the standard deviation for the sample

$n=22$ sample size

$\mu_o =36$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the true mean less than 36, the system of hypothesis would be:

Null hypothesis: $\mu \geq 36$

Alternative hypothesis: $\mu < 36$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402$