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Irina18 [472]
3 years ago
10

Solve the inequality 42<-6d

Mathematics
1 answer:
pentagon [3]3 years ago
6 0

Answer:

d < - 7

Step-by-step explanation:

given

42 < - 6d ( divide both sides by - 6 )

Remembering to reverse the inequality symbol as a consequence

- 7 > d ⇒ d < - 7

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Airida [17]
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5 0
3 years ago
-30 + 5a &lt; 16<br> A. a 9.2<br> C.<br> a &lt; 9.2<br> a&gt; -2.8<br> a &lt; -2.8
Goryan [66]

Answer:

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Hope this help...

4 0
2 years ago
What is the radius of a circle whose equation is x2 y2 8x – 6y 21 = 0?
andrew11 [14]

we know that

the standard form of the equation of the circle is

(x-h)^{2} +(y-k)^{2}=r^{2}

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

x^{2} +y^{2} +8x-6y+21=0

<u>Convert to standard form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}+8x) +(y^{2}-6y)=-21

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

(x^{2}+8x+16) +(y^{2}-6y+9)=-21+16+9

(x^{2}+8x+16) +(y^{2}-6y+9)=4

Rewrite as perfect squares

(x+4)^{2} +(y-3)^{2}=4

(x+4)^{2} +(y-3)^{2}=2^{2}

the center of the circle is (-4,3)

the radius of the circle is 2\ units

therefore

<u>the answer is</u>

the radius of the circle is 2\ units


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Answer:

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Step-by-step explanation:

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3 years ago
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