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Andrei [34K]
3 years ago
5

|2s|+19=13 Help me please

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
4 0

 \textsf{Hey there!}

\mathsf{|2s| + 19= 13}\\\textsf{Solve both sides by -19}\\\mathsf{|2s|+19+ (-19)=13+(-19)}\\\mathsf{Cancel\ out:\ 19 + (-19) \  because\ that\ gives\ you\ 0}\\\mathsf{Keep: 13 + (-19)\ because\ that\  helps\ us\ solve\ for\ our\ answer}\\\mathsf{13 + (-19) = -6}\\\mathsf{Solve\ for\ absolute\ value: |2s| = -6}\\\mathsf{Any\ absolute\ values\ CANNOT\ be\ less\ than\ 0}\\\mathsf{\boxed{\boxed{\mathsf{Thus, \ this\ make\ your\ answer\ is: \boxed{\boxed{\bf{No\ solution}}}}}}}\checkmark

\textsf{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

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Answer:

Step-by-step explanation:

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7. a

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In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one study
DIA [1.3K]

Answer:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

Step-by-step explanation:

Information provided

X_{1}=1642 represent the number of smokers from the sample in 1995

X_{2}=1415 represent the number of smokers from the sample in 2010

n_{1}=4276 sample from 1995

n_{2}=3908 sample from 2010  

p_{1}=\frac{1642}{4276}=0.384 represent the proportion of smokers from the sample in 1995

p_{2}=\frac{1415}{3908}=0.362 represent the proportion of smokers from the sample in 2010

\hat p represent the pooled estimate of p

z would represent the statistic    

p_v represent the value for the pvalue

System of hypothesis

We want to test the equality of the proportion of smokers and the system of hypothesis are:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

The statistic is given by:

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{1642+1415}{4276+3908}=0.374  

Replacing the info given we got:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

7 0
3 years ago
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