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kumpel [21]
3 years ago
12

3 1/5 divided by 4 = ? what is the answer and how did you get it

Mathematics
1 answer:
Butoxors [25]3 years ago
5 0

Answer:

31/5=6.2

6.2/4=

1.55 I hope you get it

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Evaluate sin 5pi/4<br> Thank you
kondaur [170]

Answer:

3.92699081699

Step-by-step explanation:

\frac{5(3.14)}{4}\\=15.7/4

3 0
3 years ago
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The formula for the area of a square is A = sa, where s is the length of a side.
Sliva [168]

Answer:

\sqrt{400} = 20

Step-by-step explanation:

Since the sides of a square are equal, A = s x s so taking the square root of the square provides the length of each side

6 0
2 years ago
The gross weight of a truck containing 30 pigs is 8 tons 1,123 pounds and 6 ounces. The average weight of one pig is 95 pounds 1
irakobra [83]

Answer: The net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

The weight of the empty truck is 7 tons 254 pounds 10 ounces.

Step-by-step explanation:

Since we have given that

The gross weight of a  truck containing 30 pigs = 8 tons 1123 pounds 6 ounces

Average weight of one pig = 95 pounds 10 ounces

Now,

We know that

1\text{ pound}=16\text{ ounces}

So,

\text{Gross weight of truck containing 30 pigs}\\=8\text{ tones }1123\times 16+6\text{ ounces}\\=8\text{ tons }17974\text{ ounces}

Similarly,

\text{ average weight of one pig }\\=95\times 16+10\text{ ounces}\\=1530\text{ ounces}

So, Net weight of the pigs in the truck

1530\times 30\\ =45900\text{ ounces}\\\\=\frac{45900}{16}\\\\=2868\text{ pounds }12\text{ ounces}\\\\=1\text{ ton }868\text{ pounds }12\text{ ounces }

So, the net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

Now, we'll find the weight of the empty truck is given by

\text{Gross weight of a truck containing} -\text{ Net weight of pigs in the truck}\\=8\text{ tons}1123\text{ pounds}6\text{ ounces}-1\text{ton }868\text{ pounds }12\text{ounces}\\=(8\times 2000\times 16+1123\times 16+6)-(1\times 2000\times 16+868\times 16-12)\\=273974\text{ ounces}-45900\text{ ounces}\\=228074\text{ounces }\\=7\text{ tons }254\text{ pounds }10\text{ ounces}

Hence, the weight of the empty truck is 7 tons 254 pounds 10 ounces .


4 0
3 years ago
Determine the domain of the following graph
sp2606 [1]

Answer:

[-9,3]

Step-by-step explanation:

The domain is all x-values or inputs of a function from left to right is -9 to + 3

6 0
2 years ago
how to integrate <img src="https://tex.z-dn.net/?f=e%5E%7B2s%7D%20%2ACos%20%5Cfrac%7Bs%7D%7B4%7D" id="TexFormula1" title="e^{2s}
icang [17]

Answer:

\int\limits {e^{2s} cos\frac{s}{4} ds    =\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s +  sin \frac{1}{4}  s} ))

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that  f(s) =  e^{2s} cos\frac{s}{4}

Now integrating

            \int\limits {f(s)} \, ds =  \int\limits {e^{2s} cos\frac{s}{4} ds

By using integration formula

   \int\limits { e^{ax} cos b x dx = \frac{e^{ax} }{a^{2}+b^{2}  } ( a cos b x + b sin b x )

<u><em>Step(ii):-</em></u>

 \int\limits {e^{2s} cos\frac{s}{4} ds    =   \frac{e^{2s} }{(2)^{2}+(\frac{1}{4}) ^{2}  } ( 2 cos (\frac{1}{4} ) s + \frac{1}{4}  sin \frac{1}{4}  s ))  

                    = \frac{e^{2s} }{(4+\frac{1}{16})} ( 2 cos (\frac{1}{4} ) s + \frac{1}{4}  sin \frac{1}{4}  s ))

                   = \frac{e^{2s} }{(\frac{65}{16} } ( \frac{8 cos (\frac{1}{4} ) s +  sin \frac{1}{4}  s}{4}  ))

                 = 16 X\frac{e^{2s} }{65 } ( \frac{8 cos (\frac{1}{4} ) s +  sin \frac{1}{4}  s}{4}  ))

                 =\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s +  sin \frac{1}{4}  s} ))

<u><em>Final answer:-</em></u>

\int\limits {e^{2s} cos\frac{s}{4} ds    =\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s +  sin \frac{1}{4}  s} ))

6 0
3 years ago
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