A segment XD is drawn in rectangle QUAD as shown
1 answer:
Answer:
∠XDQ : 41°
∠UXD: 139 °
Step-by-step explanation:
Allow me to rewrite your answer for a better understanding and please have a look at the attached photo.
<em>A segment XD is drawn in rectangle QUAD as shown below. </em>
<em>What are the measures of ∠XDQ and ∠UXD ? </em>
My answer:
As we can see in the photo, ∠ADX = 49° and ∠ADU =90°
=> ∠XDQ = ∠ADU - ∠ADX
= 90° - 49° = 41°
In the triangle ADX, we can find out the angle of ∠DXA
= 180° - ∠DAX - ∠ADX
= 180° - 90° - 49°
= 41°
=> <em>∠UXD = </em>180° - ∠DXA (Because UA is a straight line)
=180° - 41°
= 139 °
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( + 4)(
- 4)
To solve this question you must FOIL (First, Outside, Inside, Last) like so
First:
(x^2 + 4)(x^2 - 4)
x^2 * x^2
x^4
Outside:
(x^2 + 4)(x^2 - 4)
x^2 * -4
-4x^2
Inside:
(x^2 + 4)(x^2 - 4)
4 * x^2
4x^2
Last:
(x^2 + 4)(x^2 - 4)
4 * -4
-16
Now combine all the products of the FOIL together like so...
x^4 - 4x^2 +4x^2 - 16
Combine like terms:
x^4 - 4x^2 +4x^2 - 16
- 4x^2 +4x^2 = 0
x^4 - 16 <<<This is your answer
Hope this helped!
~Just a girl in love with Shawn Mendes