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Lyrx [107]
2 years ago
8

Tessellations

Mathematics
1 answer:
klemol [59]2 years ago
4 0

Answer:

A. Yes

Step-by-step explanation:

I calculated it logically

You might be interested in
Question Down below.
expeople1 [14]

Answer:

there equal

Step-by-step explanation:

the absolute value of 3 is 3

and the absolute value of -3 is 3

hope this helps

let me know if you need help with anymore

Have a great day!

8 0
3 years ago
I need help brosssssssssss
gavmur [86]
Answer
B. Is the answer.
5 0
3 years ago
What is the answer to this?
rodikova [14]

Answer:

tkae j ad by f then subtracr the u then add the c then multply k then say u

Step-by-step explanation:

3 0
3 years ago
(cot^2x - 1)/(csc^2x) = cos2x​
Alex787 [66]

Answer:

Step-by-step explanation:

The idea here is to get the left side simplified down so it is the same as the right side. Consequently, there are 3 identities for cos(2x):

cos(2x)=cos^2x-sin^2x,

cos(2x)=1-2sin^2x, and

cos(2x)=2cos^2x-1

We begin by rewriting the left side in terms of sin and cos, since all the identities deal with sines and cosines and no cotangents or cosecants.  Rewriting gives you:

\frac{\frac{cos^2x}{sin^2x} -\frac{sin^2x}{sin^2x} }{\frac{1}{sin^2x} }

Notice I also wrote the 1 in terms of sin^2(x).

Now we will put the numerator of the bigger fraction over the common denominator:

\frac{\frac{cos^2x-sin^2x}{sin^2x} }{\frac{1}{sin^2x} }

The rule is bring up the lower fraction and flip it to multiply, so that will give us:

\frac{cos^2x-sin^2x}{sin^2x} *\frac{sin^2x}{1}

And canceling out the sin^2 x leaves us with just

cos^2x-sin^2x which is one of our identities.

5 0
3 years ago
Which of the following estimates at a 95% confidence level most likely comes from a small sample?
dusya [7]
<span>The <u>correct answer</u> is:

A) 60% ± 18%.

Explanation:

In a confidence interval, the margin of error is given by z*(</span>σ/√n<span>), where </span>σ<span> is the standard deviation and n is the sample size.

First we <u>find the value of z</u>:

We want a 95% confidence level; 95% = 95/100 = 0.95.

To find the z-score, we first subtract this from 1:
1-0.95 = 0.05.

Divide by 2:
0.05/2 = 0.025.

Subtract from 1 again:
1-0.025 = 0.975.

Using a z-table, we find this value in the middle of the table. The z-score that is associated with this value is 1.96.

Back to our formula for margin of error, we have 1.96(</span>σ<span>/</span>√n<span>). The larger n, the sample size, is, the larger its square root is. When we divide by a larger number, our answer is smaller; this gives us a smaller margin of error.

This means that if we had a small sample size, we would divide by a smaller number, making our margin of error larger. The largest margin of error we have in this question is 18%, so this is our correct answer.</span>
7 0
3 years ago
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