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LenKa [72]
3 years ago
14

Help with 19, 19a, and 19b please

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
7 0
19b 36 is correct can’t figure out the other one
Nina [5.8K]3 years ago
3 0
The answer to 19b is 35

i’m sorry i don’t know part A
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-10(10x-12)=-9(-9x-2)-5
Viefleur [7K]

10(10x−12)=−9(−9x−2)−5
Step 1: Simplify both sides of the equation.
−10(10x−12)=−9(−9x−2)−5
(−10)(10x)+(−10)(−12)=(−9)(−9x)+(−9)(−2)+−5(Distribute)
−100x+120=81x+18+−5
−100x+120=(81x)+(18+−5)(Combine Like Terms)
−100x+120=81x+13
−100x+120=81x+13
Step 2: Subtract 81x from both sides.
−100x+120−81x=81x+13−81x
−181x+120=13
Step 3: Subtract 120 from both sides.
−181x+120−120=13−120
−181x=−107
Step 4: Divide both sides by -181.
−181x
−181
=
−107
−181
x=
107
181
Answer:
x=
107
181

7 0
3 years ago
Read 2 more answers
What is the correct factored for of x^2-9/x-3 to show a common factor can be divided out?
natali 33 [55]

Answer:

should be x^2-9/x-3

3 0
3 years ago
polygon A i simllar to polgon B. find the perimeer of polygon B if one side of polygon A is 24 A sde to polygon B is 15 and the
Gemiola [76]

Answer:

Perimeter of polygon B = 80 units

Step-by-step explanation:

Since both polygons are similar, their corresponding sides and perimeters are proportional. Knowing this we can setup a proportion to find the perimeter of polygon B.

\frac{side-polygonA}{side-polygonB} =\frac{perimeter-polygonA}{perimeter-polygonB}

Let x be the perimeter of polygon B. We know from our problem that the side of polygon A is 24, the side of polygon B is 15, and the perimeter of polygon A is 128.

Let's replace those value sin our proportion and solve for x:

\frac{side-polygonA}{side-polygonB} =\frac{perimeter-polygonA}{perimeter-polygonB}

\frac{24}{15} =\frac{128}{x}

x=\frac{128*15}{24}

x=\frac{1920}{24}

x=80

We can conclude that the perimeter of polygon B is 80 units.

8 0
3 years ago
Y is a number such that 6y = 12
nataly862011 [7]
6y = 12
y = 12/6
y = 2

:)
5 0
3 years ago
Write the function f(x) = 3x2 - 6x + 5 in vertex
weeeeeb [17]
3(x-1)^2 +2
This is your answer in vertex form, your h and k values are the vertex. Solving the function by using b/2a, we get that h is 1. ( in the equation 3 is your a, 6 is b and 5 is c.). ( 6/2(3)) = 1. We can then plug in 1 as x into the original equation and get positive 2 ( 3(1)^2 -6(1) +5) = 3-6+5 = 2. This is your vertex. In the function, your a value will always stay the same as this is your shrink or stretch. In this case, a is 3 so it will go outside the parenthesis. Put that all together and you get the function above.
Hope this helps :)
7 0
2 years ago
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