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djverab [1.8K]
3 years ago
15

Land needs to order supplies for the upcoming month. Her

Mathematics
2 answers:
Feliz [49]3 years ago
7 0

Answer:

kxjasldcsdkchdklcjhdfhdshjfhdskjkjfdskf

Step-by-step explanation:

Dahasolnce [82]3 years ago
6 0

60 of each item

Step-by-step explanation:

5 boxes of pencils, 6 boxes of markers, 15 boxes of notebooks, 10 boxes of erasers, and four boxes of folders

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Please help me....))
miskamm [114]
The first picture is for number 1 and the second one for number 2.

8 0
2 years ago
Find all values of x that make the triangles congruent. Explain your reasoning.
RSB [31]

Answer:

x = \frac{4}{5},5

Step-by-step explanation:

If both the triangles ΔABC and ΔBCD are congruent,

Corresponding sides of both the triangles will be proportional.

\frac{AB}{BD}=\frac{AC}{CD}

\frac{5x}{3x+10}=\frac{5x-2}{4x+3}

5x(4x + 3) = (5x - 2)(3x + 10)

20x² + 15x = 15x² + 50x - 6x - 20

20x² + 15x = 15x² + 44x - 20

20x² - 15x² = 44x - 15x - 20

5x² = 29x - 20

5x² - 29x + 20 = 0

5x² - 25x - 4x + 20 = 0

5x(x - 5) - 4(x - 5) = 0

(5x - 4)(x - 5) = 0

x=\frac{4}{5},5

3 0
3 years ago
Three shirts cost $9.99. How much does it cost for 8 shirts?
Olegator [25]

Answer:

Step-by-step explanation:

Mines came up as 79.78 but ion think that’s right

5 0
3 years ago
Read 2 more answers
Ben claims that 12 is a factor of 24. how can you check whether he is correct
AlekseyPX
Take 12 from 24 and if the the answer is 12 then it's a factor.
7 0
3 years ago
When n=343 college students are randomly selected and surveyed, it is found that x=110 own a car. Find a 99% confidence interval
Liono4ka [1.6K]

Answer:

The margin of error will be "0.65". A further explanation is provided below.

Step-by-step explanation:

The given values are:

n = 343

x = 110

At 99% confidence level,

\alpha = 1-99%

  =1-0.99

  =0.01

then,

\frac{\alpha}{2} =\frac{0.01}{2}

  =0.005

or,

Z_{\frac{\alpha}{2} }=Z_{0.005}

     =2.576

Now,

The point estimate will be:

⇒  \hat{P}=\frac{x}{n}

⇒      =\frac{110}{343}

⇒      =0.321

or,

⇒  1-\hat{P}=1-0.321

⇒            =0.679

The margin of error will be:

⇒  E=Z_{\frac{\alpha}{2} }\times \sqrt (\frac{(\hat{P}\times (1 - \hat{P})) }{n} )

On substituting the above values, we get

⇒      =2.576\times \sqrt{\frac{0.321\times 0.679}{343} }

⇒      =2.576\times \sqrt{\frac{0.217959}{343} }

⇒      =0.065

hence,

⇒  \hat{P}-E

⇒  0.321-0.065

⇒  0.256,0.386

6 0
3 years ago
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