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astraxan [27]
3 years ago
10

The Tiny State College Student Advisory Board has rules to the effect that the officers of the board (i.e., Chairperson, Vice-Ch

airperson, and Treasurer) must always include at least one in-state student and at least one senior. The 150 Student Council consists of 6 members: 1 in-state senior, two in-state stude who are not seniors, 1 out-of-state senior, and two out-of-state students wn not seniors. In how many ways can the officers of the Student Advisory Bog selected from these 6 Student Council members if they must obey the rules that if individual members switch offices, this produces a different Board.
Mathematics
1 answer:
BigorU [14]3 years ago
8 0

Answer:

P (6, 3) – p (6, 4) – p (6, 2) = 270

Step-by-step explanation:

The 150 student council consist of 6 members.

Included at least one in-state student and at least one senior.

There are total 6 members: in which,

1 in- state senior,

2 in state non-senior,

1 out of state senior and

2 out of state non-senior.

Total member are 6 and we selected 3. So p (6, 3)

The way team will have only non-senior = p (6, 4)

The way team will have out of state = p (6, 2)

Subtracting the total we get:

P (6, 3) – p (6, 4) – p (6, 2) = 6x5x4 – 6 x 5 x 4 x3 – 6x 5

                                             = 30 x 4 – 30 x 12 – 30

                                             = 120 – 360 – 30

                                             =- 270

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A museum had 275,608 visitors last year what is the number rounded to the nearest thousand
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2 years ago
What is the distance between point A and point B? Round to nearest tenth.
Sergeu [11.5K]

Answer:

d \approx 12.6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
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<u>Algebra II</u>

  • Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from graph.</em>

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Point B (8, 6)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>.

  1. Substitute [DF]:                    d = \sqrt{(8+4)^2+(6-2)^2}
  2. Add/Subtract:                       d = \sqrt{(12)^2+(4)^2}
  3. Exponents:                           d = \sqrt{144+16}
  4. Add:                                      d = \sqrt{160}
  5. Simplify:                                d = 4\sqrt{10}
  6. Evaluate:                              d = 12.6491
  7. Round:                                 d \approx 12.6
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