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Pepsi [2]
3 years ago
12

A college chemistry instructor thinks the use of embedded tutors will improve the success rate in introductory chemistry courses

. The passing rate for introductory chemistry is 6565​%. During one​ semester, 200200 students were enrolled in introductory chemistry courses with an embedded tutor. Of these 200200 ​students, 147147 passed the course. The instructor carried out a hypothesis test and found that the observed value of the test statistic was 2.522.52. The​ p-value associated with this test statistic is 0.00590.0059. Explain the meaning of the​ p-value in this context. Based on this​ result, should the instructor believe the success rate has​ improved?
Mathematics
1 answer:
Yuliya22 [10]3 years ago
8 0

Answer:

Step-by-step explanation:

Hello!

The chemistry instructor tested the hypothesis that the proportion of students that passed the introductory chemistry class is better with an embedded. If the known proportion for this population is 65%, the tested hypothesis is:

H₀: p=0.65

H₁: p>0.65

The calculated statistic is Z=2.52 and the associated p-value: 0.0059

Remember:

The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).

In this case:

P(Z≥2.52)=0.0059

There is no significance level, the most common one is α: 0.05 so I'll use it as an example.

To make a decision using the p-value you have to compare it to the α.

If p- value>α then you support the null hypothesis (In this case, you can say that there is no change in the proportion of students that passed the introductory chemistry class with an embedded tutor.)

If p-value≤α your decision will be to reject the null hypothesis (In this case, there is significant evidence to say that there is an improvement in the success rate of the introductory chemistry class with an embedded tutor?

Since the p-value:0.0059 is less than the significance level 0.05, you will decide to reject the null hypothesis.

I hope you have a SUPER day!

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Answer:

0.39 because it's the cheapest / least

Step-by-step explanation:

Ok so we are trying to find the least. So first line up your decimals as shown below

<u>Tens</u>          <u>Tenths</u>      <u>Hundredths</u>

<h3>   0      .        3              9</h3><h3>---------------------------------------</h3><h3>   0      .        4              1</h3><h3>---------------------------------------</h3><h3>   0      .        4              0 ---> Imaginary 0</h3><h3 />

Now fill in any empty spaces with a 0 as shown in the decimal 0.4, your decimal will still have the same amount because 0.4 = 0.40 = 0.400 no matter how many 0's you put in the decimal.

When your done with placing 0's, look at the numbers in the first column, the Tens column. As you can see we have the numbers 0, 0, 0. They're all the same so we don't have to worry about that. Now lets go to the next column, the Tenths column. We have the numbers 3, 4, 4. Remember, we are finding the least amount. we know 3 is less than 4 so the decimal with the 3 in the Tenths place is the best buy. If these numbers were the same we would go on to the next place, the Hundredths place. If 2 of the decimals had a 3 in the Tenths place, you would eliminate the decimal with no 3 in the Tenths place and go on to the next place using only the decimals you have left.

So, <em>0.39</em> is the best buy.

Hope this helps you and makes Sense! :)

This is NOT copy pasted, I actually wrote all of this so that the person reading this answer can understand what I'm trying to explain.

Thank you, and have a Great Day! ;)

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Answer:

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Step-by-step explanation:

I answered hope it helps

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