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Rudiy27
3 years ago
7

A blimp can be seen flying at an altitude of 5500 feet above a motor speedway during a race. The slanted distance directly to th

e pagoda at the startdashfinish line is d feet. Express the horizontal distance h as a function of d.
Mathematics
1 answer:
Vladimir [108]3 years ago
3 0

Answer:

The expression of h as function of x is   h = \sqrt{(d + 5500) (d - 5500)}

Step-by-step explanation:

Given as :

The distance of blimp  (AB) = 5500 feet

The slanted distance to the pagoda (BC) = d feet

The horizontal distance (AC) = h

Let the angle made between slanted distance and horizontal distance be Ф

So , cos Ф = \frac{AC}{BC} = \frac{h}{d}

And sin Ф =  \frac{AB}{BC} = \frac{5500}{d}

∵, cos²Ф = 1 - sin²Ф

So, (\frac{h}{d})^{2} = 1 - (\frac{5500}{d})^{2}

Or, (\frac{h}{d})^{2} = (\frac{d^{2}- 5500^{2}}{d^{2}})

Or,                                     h² = d² - 5500²

∴                                        h = \sqrt{d^{2}- 5500^{2}}

Or,                                     h = \sqrt{(d + 5500) (d - 5500)}

Hence The expression of h as function of x is   h = \sqrt{(d + 5500) (d - 5500)}     Answer

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Answer:

Step-by-step explanation:

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Large picnic ground:

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\frac{8}{3}=\frac{120}{y}\\\\\frac{8*15}{3*15}=\frac{120}{y}\\\\\frac{120}{45}=\frac{120}{y}

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3 years ago
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Step-by-step explanation:

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2 years ago
Read 2 more answers
[30 POINTS] Please help!!!
Len [333]

Answer:

Part 1) y=1.5x+5  

Part 2) y=-(2/3)x-(11/3)

Part 3) y=0.25x+2.75    

Part 4) y=-2x+5  

Part 5) y=0.5x-1  

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

m=3/2=1.5

point(-2,2)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

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Part 2) we know that  

If two lines are perpendicular

then

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so

m1*m2=-1

the slope of the line 1 is equal to

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Find the slope m2

1.5*m2=-1

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Find the equation of the line 2  

we have

m2=-2/3

point(-7,1)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y-1=(-2/3)(x+7)

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y=-(2/3)x-(11/3)

Part 3) we have

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point(1,3)  

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y-y1=m(x-x1)

substitute

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we know that

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substitute the values

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The slope of the line 4 is equal to -2

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in this problem we have

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The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y+2=0.5(x+2)

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Part 6)

using a graphing tool

see the attached figure

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