Using the normal distribution, it is found that 95.15% of students receive a merit scholarship did not receive enough to cover full tuition.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean 
and standard deviation 
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation for the amounts are given as follows:
The proportion is the <u>p-value of Z when X = 4250</u>, hence:
Z = 1.66
Z = 1.66 has a p-value of 0.9515.
Hence 95.15% of students receive a merit scholarship did not receive enough to cover full tuition.
More can be learned about the normal distribution at brainly.com/question/15181104
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Answer:
1/8
Step-by-step explanation:
This is a compund probability problem. You need to find the probability of each event and then multiply the probabilities together.
The probability of flipping tails is 1/2. We need three of these.
1/2 x 1/2 x 1/2 = 1/8
Answer:
32x+32
Step-by-step explanation:
In the distributive property, you have to multiply the thing outside the parenthesis to each term in the parenthesis. -4*-8x=32x and -4*-8=32, so the answer would be 32x+32
Answer:well for the first one I am not sure but I think that since four is over the x there should be 4/x + 3 so tragically I don’t know the answer but I think it should be 12 the x should be 12 because 4x3=12 so yea 12
Step-by-step explanation:and for the other one I don’t know but ima try it should be two because 2x2=4 and so y=1-2x2-4 that’s what I think sorry. I got it wrong and do good on your test for me please
