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2 years ago

8

Sravya earns $42,820 per year in take home pay. What is the most money a housing expert would advise her to spend on a monthly m

ortgage payment?

1 answer:

Margarita [4]2 years ago

3 0

Answer:

Step-by-step explanation:

the most money a housing expert would advise her to spend on a monthly mortgage payment would be 1,645

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What are the domain and range of the function?<br> f(x) = ^3 square x - 3

DerKrebs [107]

Step-by-step explanation:

$f(x) = \sqrt[3]{x - 3}$

The domain of a function are the values of $x$ that you can plug into the function $f(x)$ .

Values inside of a root must be non-negative, which means that $x - 3$ must be greater than or equal to zero. We can set up an equation to find the domain:

$x - 3 \geq 0$

$x \geq 3$

With this, we know the domain of the function is $[3, \inf)$ .

The range of a function are the values that $f(x)$ can have. Since the equation is a cube root, the value will always be non-negative, meaning the range of the function is $[0, \inf)$ .

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3 years ago

What two numbers multiply to 20 and add up to 9

prohojiy [21]

Answer:

5 and 4

Step-by-step explanation:

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3 years ago

Read 2 more answers

Percentages What percentage is R10 of R200? R10 100 X R200 <br>

Andrej [43]

R10 is 5% of R200

<h3>What percentage is R10 of R200?</h3>

The given parameters are:

R10 of R200

The percentage is calculated as

Percentage = R10/R200 * 100%

Evaluate the product

Percentage = 5%

Hence, R10 is 5% of R200

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2 years ago

I don’t get none of this work so help me please

kupik [55]

yeah. I can't see none of you work so help ME please.

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3 years ago

Using the simple random sample of weights of women from a data set, we obtain these sample statistics: nequals45 and x overbar

Tomtit [17]

Answer: (141.1, 156.48)

Step-by-step explanation:

Given sample statistics : $n=45$

$\overline{x}=148.79\text{ lb}$

$\sigma=31.37\text{ lb}$

a) We know that the best point estimate of the population mean is the sample mean.

Therefore, the best point estimate of the mean weight of all women = $\mu=148.79\text{ lb}$

b) The confidence interval for the population mean is given by :-

$\mu\ \pm E$ , where E is the margin of error.

Formula for Margin of error :-

$z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given : Significance level : $\alpha=1-0.90=0.1$

Critical value : $z_{\alpha/2}=z_{0.05}=\pm1.645$

Margin of error : $E=1.645\times\dfrac{31.37}{\sqrt{45}}\approx 7.69$

Now, the 90% confidence interval for the population mean will be :-

$148.79\ \pm\ 7.69 =(148.79-7.69\ ,\ 148.79+7.69)=(141.1,\ 156.48)$

Hence, the 90% confidence interval estimate of the mean weight of all women= (141.1, 156.48)

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3 years ago