Answer:
the 95th percentile for the sum of the rounding errors is 21.236
Step-by-step explanation:
Let consider X to be the rounding errors
Then; 
where;
a = -0.5 and b = 0.5
Also;
Since The error on each loss is independently and uniformly distributed
Then;

where;
n = 2000
Mean 







Recall:



For 95th percentile or below





From Normal table; Z > 1.645 = 0.05




the 95th percentile for the sum of the rounding errors is 21.236
All of possible ratios of boys to girls that could be made is 8:16; 4:8; 2:4; 1:2
Hope it helps, Brainliest if it <3
Answer:
Most likely the answer is
3x^2+4x-6
M+g≤40
12m+14g=x where x is his total earnings for the week
12m+12g+2g=x, so x-2g=12(m+g) and x-2g≤480. Or x≤480+2g. His earnings cannot exceed 480+2g.