Use a calculator to find the cube root of positive or negative numbers. Given a number x<span>, the cube root of </span>x<span> is a number </span>a<span> such that </span><span>a3 = x</span><span>. If </span>x<span> positive </span>a<span> will be positive, if </span>x<span> is negative </span>a<span> will be negative. Cube roots is a specialized form of our common </span>radicals calculator<span>.
</span>Example Cube Roots:<span>The 3rd root of 64, or 64 radical 3, or the cube root of 64 is written as \( \sqrt[3]{64} = 4 \).The 3rd root of -64, or -64 radical 3, or the cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).The cube root of 8 is written as \( \sqrt[3]{8} = 2 \).The cube root of 10 is written as \( \sqrt[3]{10} = 2.154435 \).</span>
The cube root of x is the same as x raised to the 1/3 power. Written as \( \sqrt[3]{x} = x^{\frac{1}{3}} \). The common definition of the cube root of a negative number is that <span>
(-x)1/3</span> = <span>-(x1/3)</span>.[1] For example:
<span>The cube root of -27 is written as \( \sqrt[3]{-27} = -3 \).The cube root of -8 is written as \( \sqrt[3]{-8} = -2 \).The cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).</span><span>
</span>This was not copied from a website or someone else. This was from my last year report.
<span>
f -64, or -64 radical 3, or the cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).The cube root of 8 is written as \( \sqrt[3]{8} = 2 \).The cube root of 10 is written as \( \sqrt[3]{10} = 2.154435 \).</span>
The cube root of x is the same as x raised to the 1/3 power. Written as \( \sqrt[3]{x} = x^{\frac{1}{3}} \). The common definition of the cube root of a negative number is that <span>
(-x)1/3</span> = <span>-(x1/3)</span>.[1] For example:
<span>The cube root of -27 is written as \( \sqrt[3]{-27} = -3 \).The cube root of -8 is written as \( \sqrt[3]{-8} = -2 \).The cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).</span>
donuts and cream puffs were 45 & 4 respectively !
<u>Step-by-step explanation:</u>
Here we have , twice the number of donuts was only 6 less than 24 times the number of cream puffs. 10 times the number of cream puffs was only 5 less than the number of donuts We need to find how many donuts and cream puffs were there . Let's find out:
Let number of donuts and cream puffs are x & y respectively ! So ,
- twice the number of donuts was only 6 less than 24 times the number of cream puffs
According to this statement equation is :
⇒ 
⇒
................(1)
- 10 times the number of cream puffs was only 5 less than the number of donuts
According to this statement equation is :
⇒ 
⇒
................(2)
Equation (1) & (2) :
⇒ 
⇒ 
⇒ 
Putting
in
:
⇒ 
⇒ 
Therefore , donuts and cream puffs were 45 & 4 respectively !
Answer:
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Step-by-step explanation:
uhhhh
.
I converted it into decimal form with a calculator and got approximately 48.9898
And if you round that, you will get the 49, which fits the inequality of
45<
< 50 since it becomes 45 < 49 < 50 which is true