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alexdok [17]
4 years ago
7

Which undefined terms are needed to define perpendicular lines?

Mathematics
2 answers:
beks73 [17]4 years ago
8 0
<span>D. Coplanar, line Parallel lines are coplanar lines that do not intersect.</span>
SVETLANKA909090 [29]4 years ago
7 0
C is the answer lil flock
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Find the diameter of a cone that has a volume of 104.67 cubic inches and a height of 4 inches. Use 3.14 for pi.
Lady bird [3.3K]

Answer:

Step-by-step explanation:

The volume of a cone is

V=\frac{1}{3}\pi r^2h

Filling in what we have:

104.67=\frac{1}{3}(3.14)r^2(4)  and simplifying a bit:

104.67=\frac{1}{3}(12.56)r^2

Multiply both sides by 3 to get:

314.01=12.56r^2

Divide both sides by 12.56 to get:

25.00079618=r^2 and take the square root of both sides to find the radius:

r = 5

If the radius is 5 and the radius by definition is half the diameter, then the diameter is 10 inches.

7 0
3 years ago
I RLLY NEED HELP FAST!!!!!!!!!!!!!!!
rodikova [14]
Hello!

You look at where J is 2 and look at where the line is for K

At J = 2, K = 20

The answer is 20

Hope this helps!
7 0
4 years ago
If j = 5 ft, k = 15 ft, m = 8.5 ft,and n = 6 ft, and the base of the figure is the shaded region, what is the lateral surface ar
Alex_Xolod [135]

Answer:

In my opinion

Step-by-step explanation:

The lateral surface area of the geometric shape formed by this net should be:

3825 ft

5 0
3 years ago
Read 2 more answers
What is the value of x?<br> 55<br> A<br> 105°<br> A. 500<br> B. 160°<br> C. 20°<br> D. 550
motikmotik

Answer:

A

Step-by-step explanation:

180-105=75

180=75+55+x

x=50

4 0
3 years ago
Read 2 more answers
Use the divergence theorem to find the outward flux of the vector field F(x,y,z)=2x2i+5y2j+3z2k across the boundary of the recta
aksik [14]

Answer:

The answer is "120".

Step-by-step explanation:

Given values:

F(x,y,z)=2x^2i+5y^2j+3z^2k \\

differentiate the above value:

div F =2 \frac{x^2i}{\partial x}+5 \frac{y^2j}{\partial y}+3 \frac{z^2k }{\partial z}  \\

        = 4x+10y+6z

\ flu \ of \ x = \int  \int div F dx

              = \int\limits^1_0 \int\limits^3_0 \int\limits^1_0 {(4x+10y+6z)} \, dx \, dy \, dz \\\\ = \int\limits^1_0 \int\limits^3_0 {(4xz+10yz+6z^2)}^{1}_{0} \, dx \, dy  \\\\ = \int\limits^1_0 \int\limits^3_0 {(4x+10y+6)} \, dx \, dy  \\\\ = \int\limits^1_0  {(4xy+10y^2+6y)}^3_{0} \, dx   \\\\ = \int\limits^1_0  {(12x+90+18)}\, dx   \\\\= {(12x^2+90x+18x)}^{1}_{0}   \\\\= {(12+90+18)}   \\\\=30+90\\\\= 120

6 0
3 years ago
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