The probability of drawing a goldfish on the first draw is 16 / ( 16 + 24 ), or 16/40, or 2/5. Supposing that the first fish drawn is actually a goldfish, then there are 15 goldfish left among 39 fish, and the probability of drawing a goldfish on the 2nd draw is 15/39, or 5/13. The (joint) probability of drawing 2 goldfish on the 1st 2 draws, without replacement, is (5/13)(2/5) = 2/13.
It already is in simplest form because the numerator and denonimator don't have a common factor to then divide them by.
Make a scenario with a yard
Answer:
(-3,-3) and at (0,6)
Step-by-step explanation:
The solution to the system of equations is where the graphs intersect
The graphs intersect at (-3,-3) and at (0,6)
Cos 52 = 0.6157
sin 42 = cos 48 = 2/3 (because 42 + 38 = 90 - complementary angles)
if tan 20,5 = 3/8 then tan 69.5 wil = 1 / 3/8 = 8/3
