Answer
A) C=5+2d
Step-by-step-explanation
If tan theta is -1, we know immediately that theta is in either Quadrant II or Q IV. We need to focus on Q IV due to the restrictions on theta.
Because tan theta is -1, the ray representing theta makes a 45 degree angle with the horiz axis, and a 45 degree angle with the negative vert. axis. Thus the hypotenuse, by the Pythagorean Theorem, tells us that the hyp is sqrt(2).
Thus, the cosine of theta is adj / hyp, or +1 / sqrt(2), or [sqrt(2)]/2
The secant of theta is the reciprocal of that, and thus is
2 sqrt(2)
---------- * ------------ = sqrt(2) (answer)
sqrt(2) sqrt(2)
Answer:
interval 41-50 and 61-70 i think
Step-by-step explanation:
To find the slope and the -intercept of the line, first write the function as an equation, by substituting for
y=10
y=0x+10
y=0x+10 , m=0
y=0x+10 , m=0 , b=10
m=0 , b=10
The slope of the line is m=0 and the y-intercept is b=10
<span> -x^2 + -14x = 49
-(x^2 +14) = 49
-[(x+7)^2 -49] = 49
</span>
