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asambeis [7]
3 years ago
5

15x + 20xy = 5x(4y) Are these two Equivalent

Mathematics
1 answer:
mixas84 [53]3 years ago
6 0

Answer:

no

Step-by-step explanation:

on the first equation there are two Xs

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Find f(x) = -3x2 + 2x - 7 if f(-1) <br> I am really confused. Can someone please help me?
Oksanka [162]
F(-1)
replace all x with -1
f(-1)=-3(-1)^2+2(-1)-7
f(-1)=-3(1)-2-7
f(-1)=-3-9
f(-1)=-12
3 0
4 years ago
jada and diego are practing the piano for sn upcoming rehersal the table list the number of minutes each of them practiced in th
Margarita [4]

Answer:

jadas practice time is 168 minutes or 2 hours 48 minutes.  Diegos practice time is 235 minutes or 3 hours 55minutes hope this helps! have a nice day and good luck with your test!

Step-by-step explanation:

4 0
3 years ago
Adam is training a group of cyclists. Each cyclist completes a 10-kilometer time trial during training. Adam records the times,
nydimaria [60]

The histogram which shows the results of the time trial is option B

<h3>Histogram</h3>

Given data:

12:32, 12:46, 13:30, 15:03, 13:43, 13:46, 14:20, 14:29, 12:34, 14:43, 15:26, 16:02, 16:16, 14:38, 16:55, 17:10, 14:26, 17:21, 17:58, 13:30

Grouping of data,:

12:00 - 12:59 = 3

13:00 - 13:59 = 4

14:00 - 14:59 = 5

15:00 - 15:59 = 2

16:00 - 16:59 = 3

17:00 - 17:59 = 3

  • The frequency is represented on the y-axis(number of cyclist)
  • The time is represented on the x-axis

Learn more about histogram:

brainly.com/question/9388601

#SPJ1

7 0
2 years ago
Uber charges 1.75 for pickup plus 0.50 per mile. Omar paid 4.25 for a ride. How many miles did he travel?
Sergeu [11.5K]

Answer:

Omar Traveled 5 miles

Step-by-step explanation:

First set up a two step equation, .50x (x is our variable for miles driven) then +1.75= 4.25. Then Subtract 1.75 from itself and from 4.25. You get 2.5, bring everything down. You are now left with .50x=2.5 divide each side by .50 . 2.5 divided by .50 equals 5 and .50 divided by itself is zero, bring down the x and the 2.5. It should now look like this x = 2.5 That is your answer.

3 0
3 years ago
Read 2 more answers
A researcher believes that the mean weight of competitive runners is about 140 pounds. A sample of 24 elite distance runners has
ExtremeBDS [4]

Answer:

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

p_v =P(t_{(23)}  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=136 represent the sample mean

s=11 represent the sample standard deviation

n=24 sample size  

\mu_o =140 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less than 140, the system of hypothesis would be:  

Null hypothesis:\mu \geq 140  

Alternative hypothesis:\mu < 140  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=24-1=23  

Since is a one left tailed test the p value would be:  

p_v =P(t_{(23)}  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

4 0
3 years ago
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