If it was reflected over the x-axis it would become (4,-3).
(12+13=25) (25+26=51) 51 is You're answer.
Hope this helps! :)
Answer:
20kg of 25% copper alloy
30kg of 60% copper alloy
Step-by-step explanation:
There are 2 kinds of metal, first metal(A) have 25% copper while the second metal(B) has 60% copper. The metalworker want to create 50kg of metal, which means the total weight of both metals is 50kg (A+B = 50). The metalworker also want the metal made of a 46% which is 23kg(0.25A + 0.6B = 0.46*50). From these sentences, we can derive 2 equations. We can solve this with substitution.
A+B = 50
A= 50-B
Let's put the first equation into the second.
0.25A + 0.6B = 0.46 *50
0.25(50-B) + 0.6B =23
12.5 - 0.25B + 0.6B =23
0.35B=23 -12.5
B= 10.5/ 0.35= 30
Then we can solve A
A= 50-B
A= 50-30
A=20
(First,Outer,Inner,Last)
25-25i+25i-25
0
The different possible mixtures can you make is 1716
.
<u>Step-by-step explanation:</u>
Given that,
- The total number of flavors available in the shop = 13 flavors
- The number of flavors you need to choose = 6 flavors
Here, we have to use the formula for combination,
nCr = n! / r! × (n-r) !
where,
- n is the total number of flavors
- r is the number of flavors you need to choose
⇒ 13C6 = 13 ! / 6! × (13-6)!
⇒ 13! / (6! × 7!
)
⇒ 13 × 12 × 11 × 10 × 9 × 8 × 7! / (6! × 7!
)
⇒ 13 × 12 × 11 × 10 × 9 × 8 / 6!
⇒ 13 × 12 × 11 × 10 × 9 × 8 / 6 × 5 × 4 × 3 × 2 × 1
⇒ 1716
Therefore, you can 1716 different possible mixtures.
