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Dafna11 [192]
3 years ago
12

In a class of 35 students, 10 students have a brother, 15 have a sister and 7 have both a brother and a sister.

Mathematics
1 answer:
stiks02 [169]3 years ago
8 0
So what is the question?
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Point A is located at (4,-7). The point is reflected over the x-axis, it’s image is located at what point ?
Alexeev081 [22]

Answer:I think it is (4,7)

Step-by-step explanation:

7 0
3 years ago
1. You are going to make one of these bags from a roll of cloth 1 meter wide. What
maks197457 [2]

Answer:

1 cm

You are going to make one of these bags from a roll of cloth 1 meter wide. What

is the shortest length that you need to cut from the roll for the bag?

Step-by-step explanation:

8 0
2 years ago
How do you find volume.<br><br><br><br><br><br> a. l x w<br> b. l x b x h<br> c. l x w x h
Fed [463]
The answer is C. L x W x H.

Hope this helps!

4 0
3 years ago
A baker had 24 boxes for donuts he ended up making 526 donuts and splitting them evenly between the boxes how many extra donuts
sertanlavr [38]

Answer:

The baker ended up with 22 extra donuts.

Step-by-step explanation:

Since the baker had 24 boxes and made 526 donuts, to split them evenly between the total number of boxes means that we need to divide the number of total donuts by the number of boxes:

526 ÷ 24 = 21 remainder of 22

Since 24 x 21 = 504 and 24 x 22 = 528 and the baker only made 526 donuts, then the most amount of donuts he can use to split them evenly with the total amount of 526 is 504.  526 - 504 = 22, so he has an extra 22 donuts that will not be in boxes.  


7 0
3 years ago
Use Lagrange multipliers to find the maximum and minimum values of
marusya05 [52]

The Lagrangian is

L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)

It has critical points where the first order derivatives vanish:

L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}

L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y

L_\lambda=x^2+y^2-4=0

From the first two equations we get

-\dfrac1{2x}=-\dfrac4y\implies y=8x

Then

x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}

At these critical points, we have

f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125 (maximum)

f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125 (minimum)

5 0
4 years ago
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