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ExtremeBDS [4]
3 years ago
11

Jeremy has 50 marbles. Sixteen percent of his marbles are blue. How many blue marbles does Jeremy have?

Mathematics
1 answer:
Umnica [9.8K]3 years ago
4 0
He has 8 blue marbles.

You find this by multiplying 50 by 0.16
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ANSWER NEEDED QUICK!<br><br> Divide: 5/8 divided by 3/4<br> 1/8<br> 5/6<br> 3/4<br> 1 1/2
Scilla [17]
5/6 I think tahts the answer hope this helps
8 0
3 years ago
Answer this question
ElenaW [278]

Answer:

12−3xStep-by-step explanation:

6 0
2 years ago
NEED HELP ASAP!! IF YOU ANSWER RIGHT YOU GET BRAINLIEST!!!!!​
lana66690 [7]

Answer:

  5x^2 +10x

Step-by-step explanation:

The area is the product of the height and width. For this exercise, it is convenient to compute the rectangle areas individually, then write their sum:

  blue rectangle area = (5x)(x) = 5x^2

  red rectangle area = (5x)(2) = 10x

Total area = 5x^2 +10x.

_____

If you start by writing an expression for the total area, expanding it requires you deal with the unlike terms separately anyway:

  5x(x +2) = 5x(x) +5x(2) = 5x^2 +10x

7 0
3 years ago
Plz help me solve these problems
leva [86]

Answer: <em><u>CAN YOU PLS MARK AS BRAINLIEST??</u></em>

a.x=11/4

b.x=6

c.x=21/2

d.x=0

Step-by-step explanation:

-2+3x+x=9-x

-2+3x+x=9

4x=9+2

4x=11

x=11/4

when you move a numerator to the other side it becomes a denominator

x+2=3/4x6

x+2=3/24

x=8-2

x=6

5-2x-12=14

2x=14-5+12

2x=21

x=21/2

1/2x=-3-1/2x+4-1

1/2x+1/2x=-3+4-1

x=0

6 0
3 years ago
Consider a single spin on the spinner shown below. A circle is split into sections 1, 2, 4, and 3. A spinner is pointing at numb
vladimir2022 [97]

Answer:

The answer is "Options A, B, and E represent mutually exclusive events".

Step-by-step explanation:

Two occurrences that can happen immediately called mutually incompatible. Let's now glance at our options and figure out where the statements are mutually incompatible events.

In Option A: You could see that landing on an unwanted portion and arriving on 2 are events that are locally incompatible, even as undesirable portion contains 3 and 4, and 2 were shaded.

In Option B: Arriving on a shaded part and falling on 3 are also mutually incompatible because there are 3 on a windows azure.

In Option C: A darkened portion and an increasing amount can land while 2 would be an even number as well as on the shaded portion. That number is very much the same.

In Option D: At the same time as 4 is greater than 3 and it is situated upon an undistressed section, landing and attracting a number larger than 3 can happen.

In Option E: Landing on a shaded part and landing on even a shaded part is an excluding event, since shaders may either be shaded or unlit.

3 0
3 years ago
Read 2 more answers
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